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Q: Whats the formula for sum and product of roots?

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the sum is -b/a and the product is c/a

parallel

Um, x2+3x-5=0? This is ax2+bx+c where a=1, b=3, and c=-5. The sum of the roots is -b/a so that means the sum of the roots is -3. Also, product of the roots is c/a. That means the product of the roots is -5. -3+(-5)= -8. There you have it.

A quadratic equation has the form: x^2 - (sum of the roots)x + product of the roots = 0 or, x^2 - (r1 + r2)x + (r1)(r2) = 0

multiply by one if ur looking for the sum and divide by one if look ing for the product, easy

find the sum and product of the roots of 8×2+4×+5=0

3x squared - 12x - 24 = 0, and -b/a = sum of the roots, and c/a = product of the roots

-9

-4,3 are the roots of this equation, so for the values for which the sum of roots is 1 & product is -12

If the given information is the sum and the product of two numbers, then the numbers are not integers, because only 1*21 or 3*7 equals 21, and their sum is different from 27. So let's write the quadratic form of an equation given the sum and the product of roots, and solve it. The sum = 27, the product = 21 x2 - (summ of the roots)x + (product of the roots) = 0 x2 - 27x + 21 = 0; a = 1, b = -27, and c = 21 x = [-b ± √(b2 - 4ac)]/(2a) the quadratic formula x ={-(-27) ± √[(-27)2 - 4(1)(21)]/[2(1)] = [27 ± √(729 - 84)]/2 = (27 ± √645)]/2 Thus, the numbers are (27 - √645)]/2 and (27 + √645)]/2.

It depends on the product of sum of what.

The product is 1254. The sum is 79.

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