The number is 199.
Statement 1: Rounding to the nearest 100 gives 200 → original number is 200 ± 50
Statement 2: Rounding to the nearest 10 gives 200 → original number is 200 ± 5
First statement can be ignored as the second is a closer range, which is a sub-range of the range of the first statement.
So the number is one of 195, 196, ..., 203, 204.
Statement 3: Sum of digits =19
Could check all the 10 possible numbers 195 - 204, but observe:
The last five numbers 200-204 all start 20- so the sum of those digits will be 2+ something, but there is no single digit that is 18, so the number cannot be one of these.
the first five numbers 195-199 all start 19- so the sum of those digits is 10 + something, which is required to be 19; so 19-10 = 9 gives the remaining digit.
Thus the number is 199.
555
-12
0
199 If it's 200 rounded to nearest ten, then the number must be between 195 and 205. Only 199 has the correct digit sum.
To round to the nearest hundred and ten both being 200 it leaves 9 possibilities. 195,196,197,198,199,201,202,203, and 204. The only one with digits adding up to 19 is 199.
226
First, 54 rounded to the nearest hundred is: 100.We round the number up to the nearest hundred if the last two digits in the number are 50 or above.
5600
199
The number would be 2666. 6 is repeated 3 times. Rounded to the nearest hundred is 2700 and rounded to the nearest thousand is 3000.
555
555
600
Remember, we did not necessarily round up or down, but to the hundred that is nearest to 321. First, 321 rounded to the nearest hundred is: 300 When rounding to the nearest hundred, like we did with 321 above, we use the following rules: A) We round the number up to the nearest hundred if the last two digits in the number are 50 or above. B) We round the number down to the nearest hundred if the last two digits in the number are 49 or below. C) If the last two digits are 00, then we do not have to do any rounding, because it is already to the hundred.
2722
-12
3200