yes the momentum of it is the same because P initial = P final ALWAYS!
butholes
liner momentum = p = mV = 2 kg * 10 m/s = 20 kg m/s
(-)11,666.67 N. To calculate this, you need to use the impulse-momentum principle, whereby the change in momentum is equal to the force multiplied by the time over which the force is applied. The change in momentum here is the final speed x the mass - the initial speed x the mass. Then divide the answer by the time (six seconds) and the answer will be the force applied (in this case the answer is negative as the force is applied in the direction opposite to the direction of the truck's motion.)
take the box off the truck and get in the back before hits wall get target
The answer will depend on the speed at which the truck travels.The answer will depend on the speed at which the truck travels.The answer will depend on the speed at which the truck travels.The answer will depend on the speed at which the truck travels.
butholes
The total momentum of the system doesn't change. In this case, it refers to the momentum of the toy truck plus the momentum of the toy car.
The sum of the momentum of the two toys before the collision will be the same as the momentum of the two toys after the collision except for some losses due to heat dissipation and frictional losses.
Total momentum
Collisions in the normal setting of life on Earth are complicated. Moving objects lose energy to air friction. Momentum in many cases is transferred to the Earth, where it becomes invisible, because it is such a tiny fraction of the Earth's total momentum. A toy truck and a toy car could collide in such a way that they both stop moving, but that does not mean that momentum has disappeared; it means that since they were moving in opposite directions in the first place, the algebraic sum of their momentum was zero in the first place. In outer space, you could see a simpler example of how momentum is transferred from one moving object to another, and how it is conserved. Momentum is always conserved, but often in such a complicated way that it is not easily perceived.
Momentum defined as p=mv.. The momentum of the truck depends on its velocity
The smaller vehicle will encounter the larger velocity change.
The principle that might apply here is momentum. Momentum is mass times velocity. What should be pointed out is that velocity is speed that has a direction vector. (If the car is moving ahead in a straight line it is traveling at "x" miles per hour "forward".) The car is moving forward and comes into contact with the truck. That seems to be where the question is looking. The mass of the car times its velocity is its momentum, and this represents the energy that it is carrying into the collision. This energy will have end up being distributed among the various parts and components of the car and the truck that are compressed, deformed and/or broken by the collision. The amount of damage will be proportional to the momentum. The more the momentum (the more the "forward" energy) of the car, the more compression, deformation and breakage there will be. Was everyone wearing seat belts? Are you in good hands?
The truck is heavier
It is a perfectly inelastic collision.Types of collisions:* Perfectly inelastic- collision in which two objects stick together after the collision so that their final velocities are the same. * Elastic-collision in which the two objects bounce after the collision so that they move separately * Inelastic-collision in which the two objects deform during the collision so that the total kinetic energy decreases , but the objects move separately after the collision.
I will assume that the collision is completely inelastic (that is, the truck and the car coalesce, moving off with the same velocity after the collision). This assumption is crucial as without it, the question cannot be solved if the inelastic collision is maintained.Let the mass of the car be m. The mass of the truck is 8m.From the principle of conservation of momentum;8m(60) = (8m + m)vwhere v is the final velocity.So, v = 8(60)/9v = 53.3 km/h
That would depend on their velocity (speed with direction), since the formula for momentum is momentum=Mass*Velocity. If they are moving at the same Velocity, the heavier of the two would have greater momentum.