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When a trinomial is factored as (x m)(x n) what is the product of m and n?
Wiki User
∙ 9y ago
It is the constant term of the trinomial.
Wiki User
∙ 8y ago
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What is the factored form of thid trinomial 2m plus 5m-12?
Assuming you mean 2m2... (2m - 3)(m + 4)
What is m2 plus m-90?
m2+m-90 = (m-9)(m+10) when factored
What is Hindu Arabic of MX?
M=1000 X=10 therefore MX=1010
How do you solve for y in the equation y equals mx plus b?
If y = mx + b, then x = (y-b)/m (for m not equal to zero).
How do you drive the equation y equals mx?
y = mx dy/dx = m The derivative is simply the constant in front of x. Here, we have indicated that to be m.
What is the factored form of thid trinomial 2m plus 5m-12?
Assuming you mean 2m2... (2m - 3)(m + 4)
How do solve for m Y equals mx plus 6?
Y = mX + 6 Y - 6 = mX (Y - 6)/X = m ==============If you had values you could get the integer that is m
How do you Solve the formula y equals mx plus b for M?
the answer is: (y-b)/x = m y = mx + b y - b = mx (y-b)/x = m
What is m2 plus m-90?
m2+m-90 = (m-9)(m+10) when factored
Can you write an equation for a non proportional linear relationship?
Yes. y = mx + c where m and c are non-zero constants.Yes. y = mx + c where m and c are non-zero constants.Yes. y = mx + c where m and c are non-zero constants.Yes. y = mx + c where m and c are non-zero constants.
What is Hindu Arabic of MX?
M=1000 X=10 therefore MX=1010
How do you change point-slope to slope-intercept?
Given the point P = (a, b) and slope m, the point-slope equation is(y - b) = m*(x - a)y - b = mx - may = mx - ma + bwhich can be re-written asy = mx + (b - ma) which is of the slope-intercept form y = mx + c in which c = b - ma.Given the point P = (a, b) and slope m, the point-slope equation is(y - b) = m*(x - a)y - b = mx - may = mx - ma + bwhich can be re-written asy = mx + (b - ma) which is of the slope-intercept form y = mx + c in which c = b - ma.Given the point P = (a, b) and slope m, the point-slope equation is(y - b) = m*(x - a)y - b = mx - may = mx - ma + bwhich can be re-written asy = mx + (b - ma) which is of the slope-intercept form y = mx + c in which c = b - ma.Given the point P = (a, b) and slope m, the point-slope equation is(y - b) = m*(x - a)y - b = mx - may = mx - ma + bwhich can be re-written asy = mx + (b - ma) which is of the slope-intercept form y = mx + c in which c = b - ma.
How do you solve for y in the equation y equals mx plus b?
If y = mx + b, then x = (y-b)/m (for m not equal to zero).
What is m in the slope y equals mx?
m is the gradient or slope of the linear equation y = mx. It is a measure of the change in y for a unit change in x.
How do you drive the equation y equals mx?
y = mx dy/dx = m The derivative is simply the constant in front of x. Here, we have indicated that to be m.
What is 2m2 - 8 factored?
\frac{1}{m-2}-1
What is the equation to find the slope of a line?
y = mx + b y - b = mx (y - b) / x = m (m is the slope, except where x = 0)
