5/36
Out of the 36 possible and equally-probable outcomes (1st die's number and 2nd die's number), 5 combinations give you a sum equal 8:
* 1st die gives a 2 and 2nd die gives a 6
* 1st die gives a 6 and 2nd die gives a 2
* 1st die gives a 3 and 2nd die gives a 5
* 1st die gives a 5 and 2nd die gives a 3
* 1st die gives a 4 and 2nd die gives a 4
Therefore the probability that the sum is greater than 10 equals 5/36.
The probability is 1, if the dice are rolled often enough.
If two dice are rolled, the probability that the sum of observed values is equal to 13 is zero. The sum of two dice can only lie between 2 and 12, inclusive.
Assuming these are regular dice, the probability is 1.
If two six sided fair dice are rolled, the sum of the result of both dice that has the lowest probability to come up is 2 and 12. P(2) = 1/36. P(12) = 1/36.
The probability of rolling 12 with 2 dice is 1 in 36. The probability of not rolling 12 with 2 dice is 35 in 36.
If you rolled 2 fair dice, the probability of having a sum of 6 is 5 over 36
7
The probability is 1, if the dice are rolled often enough.
If the dice are fair then it is 5/36.
It is 1/9.
If two dice are rolled, the probability that the sum of observed values is equal to 13 is zero. The sum of two dice can only lie between 2 and 12, inclusive.
Assuming these are regular dice, the probability is 1.
It's1/12
The two dice sum of 4: 1,3 2,2 3,1 = 3 in 36 = 1 in 12
If two six sided fair dice are rolled, the sum of the result of both dice that has the lowest probability to come up is 2 and 12. P(2) = 1/36. P(12) = 1/36.
The probability of rolling 12 with 2 dice is 1 in 36. The probability of not rolling 12 with 2 dice is 35 in 36.
Probability that the sum is 6 = 5/36 Probability that the sum is 7 = 6/36