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6mo ago

The percentage error in the area of the square will be twice the percentage error in the length of the square. This is because the error in the length affects both the length and width of the square, resulting in a compounded effect on the area. Therefore, if there is a 1 percent error in the length, the percentage error in the area would be 2 percent.

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Q: When an error of 1 percent is made in the length of a square the percentage error in the area of square will be?
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When an error of 1 percent is made in the length of square the percentage error in area of a square will be?

1% off


When an error of 1 percent is made in the length of square the percentage error in the area of a square will be?

1% off


When an error of 1 percent is made in the length of a square the percentage of error in the area of a square will be?

area= side^2 let the symbol # denote error in measurement #area/area= 2(#length/length) #area/area*100= 2(#length/length)*100 percent error in area= 2*percent error in length=2% 2 per cent


When an error of 1 percent is made in the length of a square error is?

The error in its area is then 2 percent....


What is the percentage error of 12m?

what is the percent error of 12m


What is the percentage error of a length measurement of 0.229 cm if the correct value is 0.225 cm?

What is the percent error of a estimated measurement of 0.229 cm if the actual value is 0.225 cm?


What is the percent error of 4cm?

A percent error depends on the size of the measurement as well as the error itself. It's very intuitive to think about: If you're measuring a piece of paper and you're off by 4 cm, you'll have problems; if you're measuring the moon, that's nothing. A bigger percent error is a bigger deal to an engineer. You can calculate it the same way as any percentage: Divide the error by the total length of the measurement, then multiply by 100 to convert it from a proportion to a percentage.


How do you use percentage error in a sentence?

The Percent error for this problem right here is 3% .


How do you calculate percentage error for density of pennies?

Percent error refers to the percentage difference between a measured value and an accepted value. To calculate the percentage error for density of pennies, the formula is given as: percent error = [(measured value - accepted value) / accepted value] x 100.


What makes your percent error calculated value not equal to the actual value?

You do not add the percentage error but the actual error.


The ratio of an error to an accepted value is called what?

its a percent error * * * * * No, it is the relative error. When that is multiplied by 100 it becomes a percentage error.


Is there a difference percent error and percentage error?

The difference: -age(hey, it's not wrong...)In general, probably not - percent and percentage are often used interchangeably. The context of use may warrant a difference though, if strict semantics are being followed:"Percent error" would refer to the the maximum potential difference between what a value could be, and what that value is stated to be. "Percentage error", in such a scenario, would refer to an erroneous percentage (as in, the percentage itself is incorrect).