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85 82 35 15
In this case, you're given the displacement - 3 miles, and the time - 35 minutes. With that, you can calculate the velocity: v = d/t ∴ v = 3M/35min. To find out how far he would go in 49 minutes, simply multiply that velocity by the number of minutes d = v⋅t ∴ d = (3M/35min)⋅49 min ∴ d = 3⋅49/35 M ∴ d = 147 / 35 M ∴ d = 4.2 M So at that speed, Juan would travel 4.2 miles
There is no simple answer. Suppose the numbers, in non-decreasing order are A, B, C, D, E and F then A = B = 21 25 < C < 30 D = 60 - C D < E < 35 and F = 35. There are, thus, infinitely many possible values for C, and hence for the data set.
First you need to consider that 35.00 is equal to 100 %; therefore, 1 % = .35 (35 /100=.35) then, multuply that by seven times, and give you the answer: .35 ( 1%) x 7 = 2.45 Therefore 2.45 is 7% of 35
35 x 35 is 1225 :D
35
D = 210
3/7 of 35 is 15.
YES HE'S 35 OR 36 YEARS OLD !!!!!! =D
60% or D-
D
level 35 :D!
85 82 35 15
When traveling at 35 mph it will take you 210 feet to come to a complete stop
49/84 :D
The minimum age is 35. :D