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2x2-4x+5 divided by x-1
Quotient: 2x-2
Remainder: 3
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What is the remainder when dividing by 11?
The answer depends on what you are dividing by 11.
Solve 2x2 plus 12x plus 11?
There is no rational factorisation to this expression.
How many times can 21 go into 249 with a remainder?
The quotient of dividing 249 by 21 is 11, with a remainder of 18. Therefore, 21 can go into 249 11 times with a remainder of 18.
When x3 plus 3x2-2x plus 7 is divided by x plus 1 what is the remainder?
(x3 + 3x2 - 2x + 7)/(x + 1) = x2 + 2x - 4 + 11/(x + 1)(multiply x + 1 by x2, and subtract the product from the dividend)1. x2(x + 1) = x3 + x22. (x3 + 3x2 - 2x + 7) - (x3 + x2) = x3 + 3x2 - 2x + 7 - x3 - x2 = 2x2 - 2x + 7(multiply x + 1 by 2x, and subtract the product from 2x2 - 2x + 7)1. 2x(x + 1) = 2x2 + 2x2. (2x2 - 2x + 7) - (2x2 + 2x) = 2x2 - 2x + 7 - 2x2 - 2x = -4x + 7(multiply x + 1 by -4, and subtract the product from -4x + 7)1. -4(x + 1) = -4x - 42. -4x + 7 - (-4x - 4) = -4x + 7 + 4x + 4 = 11(remainder)
How many remainders when dividing by 12?
There are 11 possible remainders (1 to 11). If something is divisible by 12, there is said to be no remainder, but this can be considered to be a remainder of 0, making 12 possible remainders.
What is the remainder when dividing by 11?
The answer depends on what you are dividing by 11.
What is 2x2 plus 3x-5?
-11
Solve 2x2 plus 12x plus 11?
There is no rational factorisation to this expression.
How many times can 21 go into 249 with a remainder?
The quotient of dividing 249 by 21 is 11, with a remainder of 18. Therefore, 21 can go into 249 11 times with a remainder of 18.
When x3 plus 3x2-2x plus 7 is divided by x plus 1 what is the remainder?
(x3 + 3x2 - 2x + 7)/(x + 1) = x2 + 2x - 4 + 11/(x + 1)(multiply x + 1 by x2, and subtract the product from the dividend)1. x2(x + 1) = x3 + x22. (x3 + 3x2 - 2x + 7) - (x3 + x2) = x3 + 3x2 - 2x + 7 - x3 - x2 = 2x2 - 2x + 7(multiply x + 1 by 2x, and subtract the product from 2x2 - 2x + 7)1. 2x(x + 1) = 2x2 + 2x2. (2x2 - 2x + 7) - (2x2 + 2x) = 2x2 - 2x + 7 - 2x2 - 2x = -4x + 7(multiply x + 1 by -4, and subtract the product from -4x + 7)1. -4(x + 1) = -4x - 42. -4x + 7 - (-4x - 4) = -4x + 7 + 4x + 4 = 11(remainder)
How many remainders when dividing by 12?
There are 11 possible remainders (1 to 11). If something is divisible by 12, there is said to be no remainder, but this can be considered to be a remainder of 0, making 12 possible remainders.
What would 2x2 plus 2x - 5 equals 0 be?
x = (-1 ± √11) / 2
What is the greatest remainder you can have when divided by 12?
If the remainder must be an integer value, then the largest remainder you can have from any equation when dividing by 12 is a remainder of 11. Example: (23 / 12 = 1 R11) 12 goes into 23 one time, and there's 11 left over. If there was more than 11, such as (24 / 12), then the answer would be 2 with no remainder.
How do you solve 6a plus 5a equals -11?
6a + 5a = -11 Combining like terms: 11a = -11 Dividing by 11: a = -1
Is the remainder of a negative number divided by a positive number negative?
A subtle point is that the remainder is always a positive number. So -7 divided by 3 is -3, remainder 2 (rather than -2, remainder -1). This is important for the date of Easter because we must often calculate the remainder when dividing into a negative number. Since in that case we are not interested in the quotient it is sufficient to calculate the negative remainder and then simply add to it the number we were dividing by. So -11 mod 3 may be calculated as: -11 divided by 3 is -3, remainder -2, so the number required is -2 + 3 = 1.
What is the answer to the equation 2x2 - 10x plus 7 equals 0?
The roots of the equation are [5 +/- sqrt(11)]/2 = 4.158 and 0.842
How can 5 plus 5 11?
It does if you are counting in base 9. 5 plus 5 equals 1 nine and a remainder of 1.
