It is called a multiple of the divisor.
The remainder of two positive integers can be calculated by first dividing one number (the dividend) by the other (the divisor) using integer division (ignoring any fractional component). Multiply this quotient by the divisor, then subtract the product from the dividend. The result is the remainder. Alternatively, while the dividend remains greater than the divisor, subtract the divisor from the dividend and repeat until the dividend is smaller than the divisor. The dividend is then the remainder.
How to solve long division problem:When dividing two numbers, the dividend and divisor; the answer is the quotient.Make note of where decimal points is in the dividend and divisor.Simplify the long division problem by moving the decimals of the divisor and dividend by the same number of decimal places.Keep the numbers lined up straight from top to bottom.After each step, be sure the remainder for that step is less than the divisor. If it is not, there is a problem - check your math.In the end, any left over is called the remainder
In division, the divisor is dividing the dividend, and the result is the quotient.dividend/divisor = quotient
Dividend divided by Divisor equals Quotient
They are called (in alphabetical order) the dividend, the divisor, and the quotient.
The remainder of two positive integers can be calculated by first dividing one number (the dividend) by the other (the divisor) using integer division (ignoring any fractional component). Multiply this quotient by the divisor, then subtract the product from the dividend. The result is the remainder. Alternatively, while the dividend remains greater than the divisor, subtract the divisor from the dividend and repeat until the dividend is smaller than the divisor. The dividend is then the remainder.
int dividend,divisor,remainder; int division(int p,int q){ int quotient=1; /*if divisor and diviend are equal then quotient=1*/ if(p==q){ remainder=0; return 1; } /*if dividend is smaller than divisor then remainder=dividend*/ if(p<q){ remainder=p; return 0; } /*shift left till divisor > dividend*/ while(p>=q){ q<<=1; quotient<<=1; } /*shift right for one time so that divisor become smaller than dividend*/ q>>=1; quotient>>=1; /*again call division recurcively*/ quotient+=division(p-q,divisor); return quotient; } int main(){ cout<<"\nEnter dividend:"; cin>>dividend; cout<<"\nEnter divisor:"; cin>>divisor; cout<<"\nQuotient:"<<division(dividend,divisor); cout<<"\nRemainder:"<<remainder; //system("pause"); return 0; }
The divisor and the dividend
How to solve long division problem:When dividing two numbers, the dividend and divisor; the answer is the quotient.Make note of where decimal points is in the dividend and divisor.Simplify the long division problem by moving the decimals of the divisor and dividend by the same number of decimal places.Keep the numbers lined up straight from top to bottom.After each step, be sure the remainder for that step is less than the divisor. If it is not, there is a problem - check your math.In the end, any left over is called the remainder
The dividend is divided by the divisor to get the quotient.
dividend and divisor
The numbers in a division problem are called dividend, divisor, and quotient.
The dividend is divided by the divisor to get the quotient.
Dividend divided by Divisor equals Quotient
In division, the divisor is dividing the dividend, and the result is the quotient.dividend/divisor = quotient
Dividend divided by Divisor equals Quotient
The three terms of a division problem is dividend, divisor, and quotient.