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As long as the mass is the same in both cases, it doesnt enter the calculations.

The height (s) from which to drop it so its velocity at impact is 100 kph (27.78 metres per second):

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s = (v2 - u2) / (2 * a)

s = 771.73 / 19.64

s = 39.29 metres

>

u = 0 (initial velocity - metres per second)

v = 27.78 (final velocity - metres per second)

a = 9.82 (acceleration due to gravity - (m/s)/s)

s = ? (distance - in this case , height)

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Q: When dropped from this height the kinetic energy when it reaches the ground is equal to if the car was traveling at 100 km h The height from which the 1000 kg car is what?
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