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That happens when only one of the two integers is negative.

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Q: When is the product of 2 integers less than or equal than to both of two factors?

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When one or both of the integers is/are zero.a*b=0 if a=0, b=0, or both a and b are equal to 0. In other words, if one or both integers are zero.

The product of two integers will be: * Zero, if one factor, or both, are zero. * Positive, if both factors have the same sign (both positive, or both negative) * Negative, if the two factors have different signs. Actually, these rules apply to all real numbers, not just to integers.

When one of the factors is less than or equal to 1, and the other is positive. Examples: 1 x 9 = 9 0 x 5 = 0 -1 x 10 = -10 If both are negative, it doesn't work: -10 x -10 = +100

if abc is 0 then at least one of the factors must be zero. since a and b are both nonzero, c must be zero.

If the question is in the context of integers and prime factorisation, then it is the number 1. If the question is about the product of two real numbers, the answer is when both factors are between 0 and 1, or when one of the factors is greater than 1 and the other is negative.

When both are positive or both are negative.

It is positive.

It is positive.

-- The product is an integer. -- If the original two integers are both positive, then the product is positive. -- If the original two integers have different signs, then the product is negative.

They're both integers.

if both are positive or if both are negative

-- Their sum and difference both have the same sign that the two integers have. -- Their product and quotient are both positive.

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