(1,2);(1,3);(1,5);(2,1);(2,2);(2,4);(2,4);(3,1);(3,3):(3,5);(3,6);(4,2);(4,4);(4,6);(5,1);(5,3);(6,2);(6,3);(6,6),there are 19 cases favourable to given event. the required probabilty is 19/36.
The probability is 29/36.
With standard dice, zero.
It is 1/18.
It is 5/11.
The probability is 1/36.
The probability is 29/36.
It is 3/4.
With standard dice, zero.
Prob(Sum is not divisible by 3) = 24/36 = 2/3
It is 1/18.
The probability of rolling doubles with two dice is 1 in 6, or about 0.167.
It is 5/11.
The probability is 1/36.
0% probability
UNLIKELY
The probability of rolling 12 with 2 dice is 1 in 36. The probability of not rolling 12 with 2 dice is 35 in 36.
The probability of 3 specific dice rolls is the probability that each one will happen multiplied together. For instance, the probability of rolling 2 then 6 then 4 is the probability of all of these multiplied together: The probability of rolling 2 is 1/6. The probability of rolling 6 is 1/6. The probability of rolling 4 is 1/6. Multiply these together and we get the total probability as 1/216