Get rid of the denominator.
True
The first step not possible in solving an equation algebraically is not to provide an equation in the first place in which it appears to be so in this case.
1. First we need to determine the least common denominator of the fractions in the given rational equation. 2. We need to take out the fractions by multiplying All terms by the least common denominator. 3. Then we have to simplify the terms in rational equation. 4. Solve the resulting equation. 5. Check the answers to make confident the solution does not make the fraction undefined.
the first step in solving the equation is to subtract the nine from the three. you will get negative 6.
If you multiply each term of the first type of equation by a common multiple of all the denominators then you will have an equation of the second type.For example, if you have 2/3*y = 4/5*x + 7/9 then multiplying by the LCM of 3, 5, 9) = 45, gives30*y = 39*x + 35: all integers!
The first step would be to find the equation that you are trying to solve!
The first step is produce the radical equation that needs solving.
I assume you mean that it continues indefinitely. ANY number which repeats periodically, ad infinitum, is a rational number. You can convert this one into a fraction (showing that it is a rational number) as follows:Let: x = 0.135135... 1000x = 135.135135... Subtract the first equation from the second one. Solving for "x", you get "x" (your original number) as a fraction.
To determine whether a polynomial equation has imaginary solutions, you must first identify what type of equation it is. If it is a quadratic equation, you can use the quadratic formula to solve for the solutions. If the equation is a cubic or higher order polynomial, you can use the Rational Root Theorem to determine if there are any imaginary solutions. The Rational Root Theorem states that if a polynomial equation has rational solutions, they must be a factor of the constant term divided by a factor of the leading coefficient. If there are no rational solutions, then the equation has imaginary solutions. To use the Rational Root Theorem, first list out all the possible rational solutions. Then, plug each possible rational solution into the equation and see if it is a solution. If there are any solutions, then the equation has imaginary solutions. If not, then there are no imaginary solutions.
Eradicate the fractions.
The difference is that first you have to understand the problem and translate it into an equation (or equations).
In algebra, you perform the operations inside parentheses first.