area of a parallelogram=base*height(base multiplied by height).
here "height" denotes the perpendicular distance between those two parallel sides one of which is taken as the base.
Parallelogram = Base*Height Triangle = 0.5*Base*HeightParallelogram = Base*Height Triangle = 0.5*Base*HeightParallelogram = Base*Height Triangle = 0.5*Base*HeightParallelogram = Base*Height Triangle = 0.5*Base*Height
That depends upon what you know about the parallelogram. If you know the area and base length, then: area of parallelogram = base X height height =area / base If you know the lengths of the two pairs of parallel sides and the angles, then trigonometry can be used. If the height is required between one pair of sides, then: height = other_side_length / sine(angle_between_sides)
Area circle: π × radius² Area triangle: ½ × base × height Area Parallelogram: base × height Area: Rectangle: length × width In a triangle, the base is any side between two vertices and the height is the perpendicular distance from this side to the third vertex. In a parallelogram the base is any side. The height is the perpendicular distance between this side and the side parallel to it.
The area of a parallelogram is the base times the height; the height must be measured perpendicular to the base. If you correctly measure the height perpendicular to the base and you get different measurements, then you are NOT dealing with a parallelogram.
It is base*vertical distance between top and bottom (the perpendicular height).
The area of a parallelogram is base x height and the area of a triangle is 1/2 x base x height. So the area of a parallelogram will always be 2 times bigger than a triangle with the same base and height.
Its area is equal to its length, multiplied by its height
The formulae are quite similar; you multiply base x height, where the height is perpendicular to the base. In the case of a trapezium, you need to calculate the average of the two bases first.
Parallelogram = Base*Height Triangle = 0.5*Base*HeightParallelogram = Base*Height Triangle = 0.5*Base*HeightParallelogram = Base*Height Triangle = 0.5*Base*HeightParallelogram = Base*Height Triangle = 0.5*Base*Height
It's the perpendicular distance between its lengths
Yes , there is a relationship between height and speed . Which is that to get fast we need to be tall . Height isn't anything weight can slow you down so speed also consists of height that is the relationship between speed and height
That depends upon what you know about the parallelogram. If you know the area and base length, then: area of parallelogram = base X height height =area / base If you know the lengths of the two pairs of parallel sides and the angles, then trigonometry can be used. If the height is required between one pair of sides, then: height = other_side_length / sine(angle_between_sides)
Area circle: π × radius² Area triangle: ½ × base × height Area Parallelogram: base × height Area: Rectangle: length × width In a triangle, the base is any side between two vertices and the height is the perpendicular distance from this side to the third vertex. In a parallelogram the base is any side. The height is the perpendicular distance between this side and the side parallel to it.
The area of a parallelogram is the base times the height; the height must be measured perpendicular to the base. If you correctly measure the height perpendicular to the base and you get different measurements, then you are NOT dealing with a parallelogram.
It is base*vertical distance between top and bottom (the perpendicular height).
height =1/width
base*height