Yes.
The rate at which the cell increases in size depends on the DNA. The ratio of the surface area (calculated: length x width x # of sides) is divided by the cell volume (calculated: length x width x height). THE VOLUME OF THE CELL INCREASES MORE RAPIDLY THAN THE SURFACE AREA, CAUSING THE RATIO OF SURFACE AREA OVER VOLUME TO DECREASE. This decrease causes cell malfunction. If the cell volume increases too much, then the ratio will decrease causing problems for the cell's regular functions.
The cell's ratio of surface area to volume would decrease. However, this scenario is extremely unlikely.
When cells get smaller, the volume (as well as mass) decreases faster than the surface area so the surface:volume increases. Cells with a high surface:volume are more effective in receiving nutrients through diffusion. A cell (assume perfect sphere) with radius 2 has a surface area of 16pi and volume of 32pi/3. A cell with radius 3 has a surface area of 36pi and volume of 108pi/3. Also relatively speaking, volume can be thought of as y=x3 and surface area as y=x2. When there is a change in x, the change is more dramatic in the volume, so small cells have high ratios and large cells have low ratios.
It decreases. As the dimensions increase by a number, the surface area increases by the same number to the power of 2, but the volume increases by the same number to the power of 3, meaning that the volume increases faster than the surface area.
It will decrease. In a larger cell, you have less surface area per volume.
As the cell grows larger the ratio of surface area to volume increases. Larger cell = more volume for the amount surface area.
The ratio decreases.
The ratio decreases.
The rate at which the cell increases in size depends on the DNA. The ratio of the surface area (calculated: length x width x # of sides) is divided by the cell volume (calculated: length x width x height). THE VOLUME OF THE CELL INCREASES MORE RAPIDLY THAN THE SURFACE AREA, CAUSING THE RATIO OF SURFACE AREA OVER VOLUME TO DECREASE. This decrease causes cell malfunction. If the cell volume increases too much, then the ratio will decrease causing problems for the cell's regular functions.
decreases i believe(:
The rate at which the cell increases in size depends on the DNA. The ratio of the surface area (calculated: length x width x # of sides) is divided by the cell volume (calculated: length x width x height). THE VOLUME OF THE CELL INCREASES MORE RAPIDLY THAN THE SURFACE AREA, CAUSING THE RATIO OF SURFACE AREA OVER VOLUME TO DECREASE. This decrease causes cell malfunction. If the cell volume increases too much, then the ratio will decrease causing problems for the cell's regular functions.
The cell's ratio of surface area to volume would decrease if its volume increases more rapidly than its surface area.
it callapses
it decreases
As size increases, the s/v ratio decreases-- the s/v ratio of a cubic cell 1mm on a side is 6, but the s/v ratio of a cubic cell 3mm on a side is only 2.
Lenght to width
As a cell increases in size the volume increases much faster than the surface area. The possible answer is C.