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Probability of no heads = (0.5)^5 = 0.03125
Probability of at least one head = 1 - probability of no heads = 1 - 0.03125 = 0.96875

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Q: When tossing 5 coins simultaneously what is the probability that at least 1 head is showing?
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Related questions

When tossing 4 coins simultaneously find the probability that at least 1 head is showing?

It is 15/16.


The probability of a head and a tail of tossing four coins simultaneously is?

1/4


When tossing 5 coins simultaneously can you find the probability that at least 1 head is showing?

Probability not at least 1 head showing is when all 5 coins are tails: (1/2)5=1/32 Therefore probability at least 1 head is showing is 1-1/32=31/32


When tossing 5 coins simultaneously what is the probability one will land heads up?

The probability that exactly one will land heads up is 0.15625


When tossing 3 coins simultaneously find the probability that at least 1 head is showing?

No matter how many coins are thrown, the possibility of having AT LEAST ONE 'head' is 50%. This changes if you specify the number of 'heads' that must be shown.


When tossing 4 coins simultaneously find the probability that exactly 2 heads is showing?

6/16 or 3/86/16 or 3/86/16 or 3/86/16 or 3/8


What is the probability of tossing two coins that are different?

The probability of tossing two coins that are different is 1 in 2, or 0.5.The probability of tossing something on the first coin is 1. The probability of not matching that on the second coin is 0.5. Multiply 1 and 0.5 together, and you get 0.5.


What is the probability of tossing seven coins at one time and having 7 of them come up heads?

The probability would be once in 128 attempts. You don't have to toss seven coins simultaneously. the 7 tosses just have to be independent of one another.


What is probability of tossing five heads from five coins?

the probability is 0.03125 or 3.123%


What is the probability of tossing two coins at the same time?

25%


What is the probability of a head in tossing three coins?

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When tossing 5 coins simultaneously find the probability that at least 1 head is showing.?

This is easiest to solve by working out the probability that no heads show and subtracting this from 1 to give the probability that at least one head shows: Assuming unbiased coins which won't land and stay on their edge, the probability of head = probability of tail = ½ → probability no heads = probability 5 tails = ½^5 = 1/32 → probability of at least one head = 1 - 1/32 = 31/32 = 0.96875 = 96.875 % = 96 7/8 %