There are a total of 36 outcomes. from 1,1; 1,2; .... to 6,5:6,6.
For these to total '7'
We have
1,6 ; 2,5 '; 3,4 ; 4,3 ; 5,2 ; & 6,1.
There are six outcomes.
So probability of a total of 7 ;
P(total 7) = 6/36 = 1/6
With two fair cubes, the probability is 1/6.
6/36
4/12
On a roll of two dice, the chance of rolling a 3 (one and two) is 2 in 36, or 1 in 18 when reduced.
If two fair number cubes are rolled, the answers are: Prob(7) = 6/36 = 1/6 Prob(11) = 2/36 = 1/18.
If you rolled 2 fair dice, the probability of having a sum of 6 is 5 over 36
It is 1/9.
The probability is 21/36 = 7/12
4/12
If the number cubes are standard dice cubes, the odds of rolling 3 ones is 1 in 216.
The experiment is not defined! The probability of the event described, when 9 or more number cubes are rolled, is 0.
I am not sure but I think 3/36
A sum that is a factor of 6 has a greater probability.to my dick
On a normal cube, the probability is 0. If there are more than 1 cubes, the answer depends on how many are being rolled for each sum.
Pr(7) = 1/36 Pr(11) = 2/36 = 1/18
If they are standard cubes - with numbers from 1 to 6 - the probability is 0.
50%
1
36