The answer is 43 and the reason why the tens digit changes is because 7 + anything over 2 will change the digit. If just added 7 + 6 it would be 13 then add 30.
1 + any whole number over 8 will change the tens digit
2 + any whole number over 7 will change the tens digit
3 + any whole number over 6 will change the tens digit
4 + any whole number over 5 will change the tens digit
5 + any whole number over 4 will change the tens digit
6 + any whole number over 3 will change the tens digit
7 + any whole number over 2 will change the tens digit
8 + any whole number over 1 will change the tens digit
9+ any whole number over 0 will change the tens digit
When you add tens to the tens digit and ones it goes ten more.
The answer would be 37.
Well, if the tens digit is 1, you have 1 option for the ones digit; if the tens digit is 2, you have two options for the ones digit, if the tens digit is 3, you have 3 options for the ones digit, etc.; up to: if the tens digit is 9, you have 9 options for the ones digit. Add all that up (1 + 2 + 3 + ... + 9).
Such a number does not exist.
Add the last digit (units digit) to twice the previous digit (tens digit). If this sum is divisible by 4, so is the original number.
Look at the digit to the right of the tens digit. If it is 5 or more, add one to the digit and add zeros in the end. Otherwise it will be 4 or less and so leave the number alone.
The tens' digit is 6. If what follows it is less than 5 then replace every digit following the tens' digit by 0s. If what follows is bigger than 5 then add 1 to the tens' digit and replace every digit following the tens' digit by 0s. If it is exactly 5 then make sure that the tens' digit is even and replace everything after it by 0s. Many naive teachers require that you round up (add 1 etc) when the next digit is 5. This introduces an upward bias and in statistically unsound. The solution is to round to odd or round to even. (See link). Mathematically, they are equivalent but, judging by the latter seems to be winning. It is the default mode in IEEE 754.
How to Calculate Rounding to the Nearest Tens Whole Number? If the ones digit (first number after decimal point) of the number is greater than or equal to 5 we add 1 to tens of number, If the ones digit of the number is less than 5 we change ones digit to 0. Example: 1026 The ones number is 6 6 is greater than 5, so we add 1 to tens. Result = 1030
Look at the tens digit. If it is 5 or more, add 100 to 9876. Then replace all the digits to the right of the hundreds digit (the tens and units digits) by zeros. The answer is therefore 9900
nothing it stays the same. For example 21 + 10 = 31
9 is in the hundreds place. The tens digit will determine whether you round this up (in which case it would become 10, which would mean zero and add 1 to the thousands digit). The tens digit is 7, so the 9 rounds up and rounded it is 5000
the answer is 1058 simply add it up?
You first add the units, then the tens.
Seriously ?... Simply add 5 to the last digit - and you have your answer !
Easy add the units and then add the tens, so 4 + 8 equals 12. 20 plus 60 = 80. Now add 12 and 80 together and you get 92.
Consider the example 234 x 26.When multiplying out, you do the ones digit first, then the tens digit:ones: 234 x 6 = 1404tens: 234 x 2 = 468and then add the results together.However, the value of the tens digit is the_digit x 10. So in this example, the tens digit is not worth two (2) but twenty (20 = 2 x 10). Thus the correct value of multiplying by the tens digit is:234 x 2 x 10 = 468 x 10 = 4680(The correct sum is: 234 x 26 = 1406 + 4680 = 6084)So when multiplying by the tens digit there will be a zero (0) on the end.Similarly when multiplying by a hundreds digit there will be two zeros (00) on the end.To avoid forgetting to do this, the zero(s) is(are) normally written in first before doing the multiplication by the tens (hundreds, etc) digit.
1. None of the digits before the tens' digit (4) should change. 2. Identify the digit in the tens' place (3). 3. Identify the digit in the units' place. 4a. If it is 0, leave the tens' digit unchanged 4b. If it is 1, 2, 3 or 4 then the number needs to be rounded down. So replace the units digit by 0. 4c. If it is 6, 7, 8 or 9 then the number needs to be rounded up. So increase the tens' digit by 1 (from 3 to 4), and replace the units digit by 0. 4d. If it is 5 then, in order to avoid introducing bias, you need to round up half the time and round down half the time. The way to do this is to make the tens' digit even: if it is already even then do nothing, if it is odd then add 1. And replace the units' digit by 0. In this case the answer is 440. Two things to bear in mind: Many schools opt for the naive approach of applying rule 4b (instead of 4d) for the digit 5. In the case of rule 1, you need to bear in mind any carry over from rounding up the tens.
Look at the thousands digit;if it is 5 or more add 10,000 to the number; if not don't add anything Replace the thousands, hundreds, tens and units digits by 0s.
It increases by 1 unless it was a 9. In that case, it becomes a 0 and the previous digit (to the left) increases by 1. Unless that was a 9 in which case ... and so on.
27 plus 81 is 108. This is because if you add the ones place, which would be the 7 of 27 and the 1 of 81 you get 8, which becomes the answer's one place. You then do the same thing except with the tens place, which are the numbers 2 and 8. Since this gives you 10, a double digit number, the 0 stays in the tens place and the 1 carries over to the hundreds place. So if you put the 8 in the ones place, 0 in the tens place, and 1 in the hundreds place, you get the number 108.
The tens digit. When there is a 4 in the tens digit, you multiply the 4 by ten, and figure out what the four is worth. Because 4 times 10 equals 40, that is what the 4 represents. The 6 is in the ones digit (1 times 6 equals 6) and the 3 is in the tenths (not tens, tenths [which is one tenth on one] ) and 3 times one tenth equals 3 tenths, or 0.3. To get the total amount, you add them all up, and get forty-six and three tenths!
194 Think of it as three separate numbers, A, B, and C (left to right). The first statement says B = C + 5 The second statement says A = B - 8 You know all three numbers have to be less than or equal to 9, and you know the first number has to be greater than or equal to 1 (otherwise you'd only have a two-digit number). So take the two statements, plus what you know about the range of the numbers, and solve for C: The first statement tells you C + 5 <= 9, subtract 5 from both sides and C <= 4 The second statement tells you C - 3 >=1, add 3 to both sides and C >= 4 So the ones digit is 4 The tens digit is 4 + 5 = 9 The hundreds digit is 9 - 8 = 1
It comes up to 100s 10 and units. start of with units. so add the 5. then do the tens. add antoher 5. That's 55... Finally, Do the 100s. Add 1 More 5. So You Got The Answer! 555!
Seveenteen tens is 170 just add 0.