Yes. Math is all about patterns. Every number larger than 1 will make the product larger than the original integer. I could describe this with a limit, but I'll hold off... As the multiplier gets closer to 1, the product gets closer to the original number. Until you hit 1, when it is equal. So if we look at numbers less than 1, we are force to conclude that the produce must be less than the original number, by trichotomy. Meaning there is no other choice: it can't be bigger or the same, so it must get smaller. Hope that clarifies.
The product would always be 0.
No, the product will always be even.
its always the same
The product is not always greater than 1.
The operation that will always have the result in value of 1 for any nonzero number is Inverse Operation of Multipication.
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Actually the product of a nonzero rational number and another rational number will always be rational.The product of a nonzero rational number and an IRrational number will always be irrational. (You have to include the "nonzero" caveat because zero times an irrational number is zero, which is rational)
Yes, always.
Yes, always.
It is always irrational.
The product of an irrational number and a rational number, both nonzero, is always irrational
Let's say that the nonzero real number is n. Then the reciprocal would be (1/n). So the product is the following n*(1/n)=(n/n)=1 In conclusion the product of any nonzero real number and it's reciprocal is always 1.
The product would always be 0.
The product of any nonzero real number and its reciprocal is the number 1. This can be mathematically given as n multiplied by 1/n, where n represents the nonzero real number. The product of these two terms is 1.
The only generalisation posible is that it will always be a rational number. The product can be positive or negative; it can be a fraction or an integer, it can be larger or smaller.
No, the product will always be even.
A rational number is always the result of dividing an integer when the divisor is nonzero.