Compatible numbers would be easier. Rounding gives you 14 x 47. Compatible numbers could be 13 x 50 which would be closer to the actual product.
The best way to estimate a quotient using compatible numbers is to first understand how compatible numbers work. They are numbers that are close in value to the actual numbers and are easily added, subtracted or divided.
the purpose of rounding numbers is that you can get closer to the actual answer
What are compatible fractions? Round the whole number to the closest compatible number to the denominator. Compatible numbers are numbers that are close in value to the real number that would make it easier to find an estimate calculation. compatible numbers are numbers that are a like or can compared like fact families! Compatible numbers When estimating, compatible numbers are numbers that are close in value to the actual numbers, and which make it easy to do mental arithmetic. In mathematics, compatible numbers are the numbers that are easy to add, subtract, multiply, or divide mentally. Compatible numbers are close in value to the actual numbers that make estimating the answer and computing problems easier. We can round the numbers to the nearest ten, hundred, thousand or ten thousand to make them compatible numbers. For instance, if we have to add 493 and 549, we can make the numbers compatible by rounding them up to the nearest tens or hundreds. 490 and 550 (rounded to the nearest tens) or 500 and 500 (rounded to the nearest hundreds) are much easier to solve. So, we know the answer is about 1040 or 1000. Let us see some examples to understand how we can perform subtraction, multiplication and division using compatible numbers. Subtraction: Find the difference between 376.5 and 612.2 Here, we cannot find the difference between 376.5 and 612.2 easily as they are not compatible. So, we make the numbers compatible by rounding both the numbers to the nearest tens. Multiplication: Find the product of 24.3 and 18.7. It is difficult to find the product of 24.3 and 18.7 mentally and quickly. So, we use compatible numbers and find the which is closer to the actual answer. Division: Divide 856 by 33. To find the answer to 856 ÷ 33, will take us time as we need to divide to get the answer. However, if we make the numbers compatible, we can mentally find an answer close to the actual answer as shown. Fun Facts Compatible numbers help in simplifying the calculation of an estimate only.
Rounding is closer because the amount added to one number is the same as the amount subtracted from the other number which makes the answer match exactly.
Compatible Numbers are numbers that are close in value to the actual numbers and easy to add, subtract, multiply or divide mentally
Rounding off, 80 x 60 = 4800. The actual product is 4698.
In arithmetic, estimate usually means rounding the numbers so they're easier to manipulate. Example: Estimate the sum of 432 and 267. You can round them to 430 and 270 and estimate the sum as 700. You could also round them to 400 and 300 and estimate the same total. To estimate a difference, just subtract them. 430 minus 270 is 160. The actual sum is 699 and the actual difference is 165, so your estimates came pretty close.
Compatible numbers are numbers that are close in value to the actual numbers and easy to add, subtract, multiply, or divide mentally.So a logical compatible number for 77 would be 80.
9 x 500 = 4500 and 9 x 600 = 5400, so you know the answer will be close to halfway between those two numbers. The actual answer is 4860.
2 x 6300 = 12,600 The actual answer is 12,508.
Yes, it would help when rounding. I rounded 0.8 up to 1 and 412 down to 400. 1*400=400 The actual answer: 0.8*412=329.6
I'd choose 20 and 30 and estimate the product at 600. The actual answer is 625.
You round the two numbers you are multiplying and try it. Lets use 16 and 13 and round to the nearest ten. We would round 16 to 20, and 13 to 10. Then we multiply 20 and 10 and get 200. So the answer would be around 200. The actual answer is 208 by the way.
Yes, you round 158 to 160, and 41 to 40, and divide. Now, do the actual division (perhaps with a calculator), to see how close the estimate is. Practice with several similar divisions, to get a "feel" of how much rounding will result in how much of an error.
An actual measurement is going to be more accurate than an estimate.
Compatible number is one that is near the actual number, but is easier to use for addition, subtraction, multiplication, or division. In other words, it is easy to use for estimating the answer to an arithmetic problem. Example: 38 + 23 A compatible number for 38 might be 40 A compatible number for 23 might be 20 (or 25) The sum of the compatible numbers would be 60 (or 65). So you know the answer will be near there. If you choose 40 and 20, you know that one of your compatible numbers is a little too high, and the other is a little too low. So your estimate of the answer (40+20=60) will be pretty close. (Your estimators are high by 2 and low by 3, so you know your answer is low by 1. It is really 61, not 60.) If you choose 40 and 25, you know that both of your compatible numbers are a little too high, so your answer will be a little more high. As it turns out, both "estimates" are high by 2, so the estimated answer (65) is high by 2+2=4. The actual result is 61 = 65-4
First of all, the two numbers are quite a long way from the ones whose quotient you are trying to estimate. Also, 8100 is smaller than 9269 so your estimate is going to be smaller than the actual value. And then 90 is bigger than 88 and is the denominator. This will make the estimate smaller still. Both the compatible numbers selected will reduce the stimate. They should be selected so that the effect of one acts in the opposite direction to that of the other. So, if you must use 8100, the select the second number which is smaller than 88. Or, if you must use 90, the other number should be greater than 9269.
The Answer will be lower the the actual sum
Type the actual number
Sometimes an actual count is too difficult, for example, at a rally. Furthermore, an estimate meets the requirements.
Apparently a magnitude estimate is just a estimate just closer to the actual answer.