(3/4, 0) and (5/2, 0)
Solved with the help of the quadratic equation formula.
10
By completing the square y = (x+3)2+1 Axis of symmetry and vertex: x = -3 and (-3, 1) Note that the parabola has no x intercepts because the discriminant is less than zero
x axis
It is x^2 - 5 which, if plotted on the x-y plane will be a parabola which is symmetric about the y axis and has its apex at (0, -5) .
The zeros of a polynomial represent the points at which the graph crosses (or touches) the x-axis.
Equation: y = 8x^2 -26x+15 Equation when factorized: y = (4x-3)(2x-5) When x = 0 then y = (0, 15) which is the point of intersection on the y axis When y = 0 then x = (3/4, 0) and (5/2, 0) which are the points of intersection on the x axis
They touch each other at (0, 100) on the x and y axis.
the origin
Yes, you can consider it a relation between the points on the x-axis, and the points on the y-axis. In fact, ANY subset of R squared (in other words, any subset of the points on a plane), including the empty set, sets that contain single points, and larger sets, can be considered a relation in R squared (i.e., two sets of real numbers).
The origin.
The Origin (0,0)
y=6x² is already solved. the parabola will touch the x-axis at x=0.
The origin
Cuts through the y axis at: (0, -12) Cuts through the x axis at: (-3, 0) and (4, 0)
x-intercept
No, in the Cartesian coordinate system it would show a vertical line whose intersection of the x-axis is 4.
its a simple parobola symmetric about y axis, having its vertex at (0,-4). we can make its graph by changing its equation in standard form so that we can get its different standard points like vertex, focus, etc.