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Q: Where is the center of the circle given by the equation x plus 4 squared plus y plus 6 squared equals 49?

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(-4,3)

The center of the circle given by the equation (x - 3)2 plus (y + 2)2 = 9 is (3,-2).

You are describing a circle, with its center at the origin and a radius of 4 (the square root of 16)

The centre is (-5, 3)

The equation describes a circle with its centre at the origin and radius = âˆš13. Each and every point on that circle is a solution.

no

I think this means (x+7)squared + (y-5)squared =4squared, which represents a circle centred at -7,+5

The area of a circle is defined by the equation A = πr^2 where π = pi (3.14...) A = Area r^2 = radius squared So, the radius of a circle squared multiplied by pi equals the area.

x2 + y2 = 49

No. C = 2*pi*r is the equation representing the circumference of a circle. The area of a circle is equal to pi*(r^2).

Area of a circle equals pi (~3.14) multiplied by the radius squared. So to find the area of that circle your equation is (3.14)(3)^2 which equals approximately 27.

56

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