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We need to complete the square to find the vertex of this parabola.

X^2 + 2X + 5 = 0

X^2 + 2X = -5

halve the coefficient of the linear term ( 2X ) and square it perfectly and add to other side

(X + 1)^2 = -5 + 1

(X + 1)^2 = -4

(X + 1)^2 + 4 = 0

Vertex is....

X = -1

Y = 4

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13y ago
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Q: Where is the vertex of the graph of y equals x2 plus 2x plus 5 located?
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