We need to complete the square to find the vertex of this parabola.
X^2 + 2X + 5 = 0
X^2 + 2X = -5
halve the coefficient of the linear term ( 2X ) and square it perfectly and add to other side
(X + 1)^2 = -5 + 1
(X + 1)^2 = -4
(X + 1)^2 + 4 = 0
Vertex is....
X = -1
Y = 4
It is a parabola with its vertex at the origin and the arms going upwards.
The vertex is at (-1,0).
The vertex has a minimum value of (-4, -11)
The equation is linear and so has no vertex.
The vertex is at the point (0, 4).
It is a parabola with its vertex at the origin and the arms going upwards.
The vertex is at (-1,0).
Interpreting that function as y=x2+2x+1, the graph of this function would be a parabola that opens upward. It would be equivalent to y=(x+1)2. Its vertex would be at (-1,0) and this vertex would be the parabola's only zero.
The vertex of the graph Y 3 X-12 plus 2 would be -1/3 and -4/3. This is taught in math.
The vertex has a minimum value of (-4, -11)
The equation is linear and so has no vertex.
The vertex is at the point (0, 4).
The vertex of the graph Y 3 X-12 plus 2 would be -1/3 and -4/3. This is taught in math.
-2-5
y = x +1 is the equation of a straight line and so has no vertex.
It is a straight line with gradient -A/B and intercept C/B.
(3, -21)