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There are 300 three digit numbers that are divisible by neither 2 nor 3.

There are 999 - 100 + 1 = 900 three digit numbers.

100 ÷ 2 = 50 → first three digit number divisible by 2 is 50 × 2 =100

999 ÷ 2 = 499 r 1 → last three digit number divisible by 2 is 499 × 2 = 998

→ there are 499 - 50 + 1 = 450 three digit numbers divisible by 2.

100 ÷ 3 = 33 r 1 → first three digit number divisible by 3 is 34 × 3 = 102

999 ÷ 3 = 333 → last three digit number divisible by 3 is 333 × 3 = 999

→ there are 333 - 34 + 1 = 300 three digit numbers divisible by 3.

The lowest common multiple of 2 and 3 is 6, so these have been counted in both those divisible by 2 and those divisible by 3.

100 ÷ 6 = 16 r 4 → first three digit number divisible by 6 is 17 × 6 = 102

999 ÷ 6 = 166 r 3 → last three digit number divisible by 6 is 166 × 6 = 996

→ there are 166 - 17 + 1 = 150

→ there are 450 + 300 - 150 = 600 three digit numbers that are divisible by either 2 or 3 (or both).

→ there are 900 - 600 = 300 three digit numbers that are divisible by neither 2 nor 3.

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Q: How many positive three digit integers are divisible by neither 2 nor 3?

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Related questions

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100 to 999 is your range. there are 900 integers in this range. 450 are not divisble by 2 ( the odd ones). 600 are not divisble by 3. half of these are even so only an additional 300 integers are not divisble by 3 alone. so 450 & 300 =750

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They are 3-digit positive integers.

10 of them.

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Positive integers are greater than negative integers. For positive integers: * The integer with more digits is larger. * If two integers have the same length, compare the first digit. If the first digit is the same, compare the second digit, then the third, etc., until you find a difference. In each case, the integer with the larger digit (at the first position where you find a difference) is the larger one.

there are 999 - 100 + 1 = 900 positive triple digit positive integers, between 100 and 999.(e.g. there are 102 - 100 + 1 = 3 triple digit integers between 100 and 102,namely 100, 101 and 102.)multiply that by 2 to take in consideration of the negative integers,you have 1800 triple digit integers.

There are 200 positive four digit integers that have 1 as their first digit and 2 or 5 as their last digit. There are 9000 positive four digit numbers, 1000 through 9999. 1000 of them have 1 as the first digit, 1000 through 1999. 200 of them have 2 or 5 as their last digit, 1002, 1005, 1012, 1015, ... 1992, and 1995.

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