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The gravitational force is.

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Q: Which is the main force that causes a toy car to roll down a ramp?
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What is main force tht causes a to to roll down a ramp?

Gravity


With how much force does a ramp push a ball rolling down it?

A ramp exerts no force, just gravity.


Why would a crayon roll down a ramp but need force to move up a ramp?

The heavy the crayon, it will roll down but it needs force to move it back up


What if The force of friction acting on a cart on a ramp is exactly balanced by the force of gravity acting on the cart down the ramp?

The cart stays where it is and doesn't move.


In Lab 1 what force slowed the car down after it came down the ramp?

friction


Why does it apply more effort when a boy pushes a load up a ramp than a boy pushing down the ramp?

Even though gravity wants to pull the boy and the load strait down the wedge shape under him and the load causes a higher amount of resistance by creating a downward force while going up. This force is a help to the boy and load going down.


Suppose a box is sliding down a ramp How many force vectors does the box have?

It has 3


How does the mass of a toy car affect its speed going down a ramp?

The weight of the car will cause the force of gravity to push it down with seemingly more force than the lighter car. And so this would make the car go faster down a slanted surface, which is the ramp.


When the toy car is placed at the top of the ramp what force acts upon the car to make it slide donw the ramp?

gravity pulls it down....but of course inertia


When a ramp is at a angle of 10.5 degrees what will be the applied force?

The applied force will depend on the required force, and the angle to the ramp (or the horizontal) at which the force is applied.


A box slides down a 35 degrees ramp with an acceleration of 1.14 ms2 Determine the coefficient of kinetic friction between the box and the ramp?

Resolve the weight into x and y componentsThe x component is the force which pushes it down and causes it to acclerateThe y component gives the normal forceFn=mgcos(A)Then the force acting sidewards Fx=mgsin(A)Total force = mgcos(A)-frictional forceFrictional force = umgsin(A)Therefore total force = mgcos(A)-umgsin(A)=mam[gcos(A)-ugsin(A)]=maso a=gcos(A)-ugsin(A)gcos(A)-a=ugsin(A)u=(gcos(A)-a)/gsin(A)


What will happen to the effort force if the height of a ramp is increase?

More force will be required to push an object along the ramp.