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Q: Which number could be a reminder for a problem with a divisor of 8?

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When 6 appears in an arithmetic problem, it could be a divisor, a quotient, a factor, a dividend, a subtrahend, a minuend, an exponent, a product, or a couple of other things. That's one of the beauties of our number system --- any number can show up in any position, and can take on any role, in a numerical calculation. Show us how the '6' fits into a problem, and we can see what function it has in that particular problem.

Only 3 non-zero remainders.1, 2, and 3 are the only possible non-zero remainders since any number greater than or equal to the divisor could also be divided, to result in a new quotient. A remainder of zero, means that the dividend is divisible by the divisor (the divisor is a factor of the number)

If the remained was bigger than the divisor than the divisor could still be taken out of the remainder

Because if the remainder was larger than the divisor, then the divisor could go into the dividend again.

37

Since 2 is a prime the only numbers that can go in it are 1 and 2, where 9 has 1,3,and 9. The greatest common divisor of them would be 1 because it is the only number they could share.

Can you clarify ?100.00000 is a number i guess technically speaking you could make it into a problem but it looks like a solution..If your looking from a problem out of that number it could be 100.0000/1

Because if the remainder is greater, then you could "fit" another divisor value into it. if they are equal, then you can divide it easily. Thus, the remainder is always lower than the divisor.

Because if the remainder is greater, then you could "fit" another divisor value into it. if they are equal, then you can divide it easily. Thus, the remainder is always lower than the divisor.

The remainder is the number that is left over after the initial value has been divided as much as it can. If any numbers greater than 48 were present as a remainder, then these could be divided further into 48. If 48 is present as the remainder, then this can be divided by 48 to give 1, leaving no remainder. Thus, the largest possible remainder if the divisor is 48 is 47.

There a number of things depending on the age of the engine. The sparkplugs of an older engine could be poorly gapped, fouled or just need to be replaced. The problem could also be the distributor cap could also be the problem. In a newer car the problem could be injecters or any number of sensers. In any car the problem could be wires.

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