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Which of these formulas is correctly rewritten from the original formula to solve for c a equals 2bc - d?

Updated: 4/28/2022

Yoyoyoitsmayo ∙

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∙ 9y ago

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c= (a+d) / 2b

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∙ 9y ago

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lolokay ∙

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∙ 2y ago

c = ( a + d ) / 2b

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Q: Which of these formulas is correctly rewritten from the original formula to solve for c a equals 2bc - d?

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Which of these formulas is correctly rewritten from the original formula to solve for b a 3b - 2c?

1

Which of these formulas is correctly rewritten from the original formula to solve for c?

a=2 BC - d is c=2(a + b)

Which of these formulas is correctly rewritten from the original formula to solve for c a equals 2b plus c?

c= a-2b

A equals 2b plus c Which of these formulas is correctly rewritten from the original formula to solve for c?

a-2b=c

Which of these formulas is correctly rewritten from the original formula to solve for b a equals 3b - 2c?

1

Related questions

Which of these formulas is correctly rewritten from the original formula to solve for b a 3b - 2c?

1

Which of these formulas is correctly rewritten from the original formula to solve for c?

a=2 BC - d is c=2(a + b)

Which of these formulas is correctly rewritten from the original formula to solve for c a equals 2b plus c?

c= a-2b

A equals 2b plus c Which of these formulas is correctly rewritten from the original formula to solve for c?

a-2b=c

Which of these formulas is correctly rewritten from the original formula to solve for d a equals 2bc plus d?

d=a-2bc

Which of these formulas is correctly rewritten from the original formula to solve for c if a equals 2bc - d?

(a+d)/2b=c

Which of these formulas is correctly rewritten from the original formula to solve for b a equals 3b - 2c?

1

What formula is correctly rewritten from the original formula to solve for d?

d = a - 2bc

Which formula for a 2b c is correctly rewritten from the original formula to solve for c?

None.

Which formula for a 2bc d is correctly rewritten from the original formula to solve for b?

None.

What formula is correctly rewritten from the original formula a 2bc d to solve for d?

d = a - 2bc

Which of these formulas is correctly rewritten from the original formula to solve for b a equals 2bc plus d?

If a=2bc+db= (a - d) / 2c If a=2b+c b=1/2(a-c)

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Which of these formulas is correctly rewritten from the original formula to solve for c a equals 2bc - d?

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