None of them. All of them.
I can divide each one of them by 1 and get no remainder.
I can divide each one of them by 5 and get a remainder.
The problem is your question is too vague.
1 and 5.
There are no such numbers. Any number can be divided by SOME number without a remainder. For a start, you can divide any number except zero by itself, without a remainder. You can also divide any number by 1 - also, without a remainder.
1, 2, 17, 34, are numbers that divide into 34 without a remainder.
Because the only whole numbers that divide into 17, without remainder, are 1 and 17 itself.
Since 5 is a prime number only the numbers 1 and 5 divide it without a remainder.
8 not divide into 36 without a remainder.
1, 2, 4, 8 divide into 8 without a remainder.
1 and 5.
1 and 5.
These six numbers: 1 2 5 10 25 and 50.
There are no such numbers. Any number can be divided by SOME number without a remainder. For a start, you can divide any number except zero by itself, without a remainder. You can also divide any number by 1 - also, without a remainder.
1, 2, 17, 34, are numbers that divide into 34 without a remainder.
Four: 1 5 31 and 155.
Because the only whole numbers that divide into 17, without remainder, are 1 and 17 itself.
Since 5 is a prime number only the numbers 1 and 5 divide it without a remainder.
1 and 5.
The only "factors" of 7 ... the only numbers that can divide into 7 evenly without a remainder ... are 1 and 7.