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Q: Which outcome is least likely to occur on a single spin 1 an odd number 2 a prime number 3 a perfect square 4 a number divisible by 2?

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Probability; Possibility/ Likeliness of an outcome

33 is not as it is divisible by 3 and 11 1 is because the only thing 1 is divisible by is itself, making it the only prime number to be a perfect square.

A prime number is a number (except 1) that cannot be the outcome of any number multiplied by a number. An even number is a number that is divisible by 2.

Converse:If a number is divisible by 3, then every number of a digit is divisible by three. Inverse: If every digit of a number is not divisible by 3 then the number is not divisible by 3? Contrapositive:If a number is not divisible by 3, then every number of a digit is not divisible by three.

Just think of one. All numbers are divisible. But that's probably not what you wanted to know. It's more likely you want to know how to find what a number is divisible by. For that, it is necessary to familiarize yourself with the rules of divisibility. If the number is even, it's divisible by 2. If the sum of the digits is a multiple of 3, the whole number is divisible by 3. If the last two digits are a multiple of 4, the whole number is divisible by 4. If the last digit is a 0 or a 5, the whole number is divisible by 5. If the number is even and divisible by 3, it's divisible by 6. If the last digit doubled subtracted from the rest is a multiple of 7, the whole number is divisible by 7. If the last three digits are a multiple of 8, the whole number is divisible by 8. If the sum of the digits is a multiple of 9, the whole number is divisible by 9. If the number ends in 0, it's divisible by 10.

There is no such number. Since 6 is divisible by 3, then any number that is divisible by 6 automatically has to be divisible by 3.

In the case of equally likely outcomes, it represents the number of times out of a denominator number of trials, that you will get a favourable outcome.

Any prime number - by definition such numbers are divisible by 1 and the number itself. As a matter of fact, only perfect squares can have an odd number of factors.

If the sum of the digits of a number is divisible by 3, then the number is divisible by 3.

It is divisible by 6

999 is divisible by 9, but not by six; the next lower number divisible by 9 is 990, which is also divisible by 6, so that's the answer. Some shortcuts for divisibility: 0 is divisible by any number. If the last digit of a number is divisible by 2, the number itself is divisible by 2. If the sum of the digits of a number is divisible by 3, the number itself is divisible by 3. If the last TWO digits of a number are divisible by 4, the number itself is divisible by 4. If the last digit of a number is divisible by 5, the number itself is divisible by 5. If a number is divisible by both 2 and 3, it is divisible by 6. If the last THREE digits of a number are divisible by 8, the number itself is divisible by 8. If the sum of the digits of a number is divisible by 9, the number itself is divisible by 9. 990: 9+9+0=18, which is divisible by 9, so 990 is divisible by 9. 18 is also divisible by 3, so 990 is divisible by 3, and since 990 ends in 0 it's also divisible by 2, meaning that it's divisible by 6 as well.

A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.

Well, there is 16, 64, 144, above is answered by the first person... In this problem, the squared number must be a whole number and divisible by 4. 20^2 is 400. And there are 4, 8, 12, 16 ,20; 5 number divisible by 4. and 23^2 is already 529. the next number divisible by 4 is 24 which is over 500. So there are 5 numbers. They are 16, 64, 144, 256, 400.

If a number is not divisible by 3 then it is not divisible by 9.

If a number is even (divisible by 2) and divisible by 3, then it must also be divisible by 6.

The most likely answer is "Perfect square".

Every number is divisible by 9 but the answer wont necessarily be a whole number.

If the last two digits of a number are divisible by four, the whole number is divisible by four.

A number is divisible by 2 if it is an even number. That is, if the last digit is divisible by 2.

No odd number can be evenly divisible by 6. Since 6 is divisible by 2, any number that is divisible by 6 will automatically be divisible by 2.

A number is divisible by 4 if the last two digits form a number that is divisible by 4, for example 612 is divisible by 4 (because 12 is divisible by 4).

If the number formed by the last three digits is divisible by 8. Alternatively, if the number is divisible by 2, the quotient is divisible by 2 and that quotient is divisible by 2.

Yes, every number that's divisible by 9 is divisible by 3

A divisible number is a number that is capable of being divided.