83, 3, 2
88
It is: 17+19+23+29 = 88
88=2x2x2x11
To find the hcf of three numbers you first need to write them as the product of their prime factors: 11 = 11 88 = 2x2x2x11 44 = 2x2x11 The next step is to identify any common prime factors. In this case, all three numbers have a prime factor of 11. Therefore the hcf of 11, 88 and 44 is 11.
2 x 2 x 2 x 11 = 88
88
41 + 47
83, 3,and 2 are prime numbers which add up to 88.
It is: 17+19+23+29 = 88
17 + 19 + 23 + 29 = 88
11x2x2 or 11x 22
88=2x2x2x11
To find the hcf of three numbers you first need to write them as the product of their prime factors: 11 = 11 88 = 2x2x2x11 44 = 2x2x11 The next step is to identify any common prime factors. In this case, all three numbers have a prime factor of 11. Therefore the hcf of 11, 88 and 44 is 11.
No, they are not relatively prime.
88 is the sum of those two numbers.
The prime factorization of 88 is 2^3 * 11, where 2 and 11 are prime numbers. This means that 88 can be expressed as the product of these prime numbers raised to their respective powers. In this case, 2 is raised to the power of 3 because it appears three times in the prime factorization of 88.
2 and 11