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Any type of rhombus has perpendicular diagonals. Please note that squares are a type of rhombus.

Q: Which two quadrilaterals have perpendicular diagonals?

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No, the only quadrilaterals that I can think of to have perpendicular diagonals are:KiteRhombusSquare (special case of a rhombus)

rhombus and a square

They are squares and rhombuses

A parallelogram.

The most obvious types of quadrilaterals that have perpendicular diagonals are those with two pairs of adjacent sides the same length - squares, rhombuses, and "kite" shapes.These are all special cases of "orthodiagonal" quadrilaterals. All orthodiagonal quadrilaterals will adhere to the rule that the sum of the squares of the lengths of two opposite (nonadjacent) sides will equal the sum of the squares of the lengths of the other two sides; for successive sides of lengths a, b, c, and d, we have:a2 + c2 = b2 + d2This formula will be true for all orthodiagonal quadrilaterals and any quadrilateral for which this is true will be orthodiagonal (i.e. the diagonals will be perpendicular).

Related questions

A square, a rhombus and a kite are all 4 sided quadrilaterals that have perpendicular diagonals.

If a quadrilaterl has a perpendicular diagonas it is a roumbus, also kite has perperndicular diagonals

No, the only quadrilaterals that I can think of to have perpendicular diagonals are:KiteRhombusSquare (special case of a rhombus)

rhombus, kite, square

Squares, Rectangles, and Rhombuses.

They are squares and rhombuses

rhombus and a square

A parallelogram.

The most obvious types of quadrilaterals that have perpendicular diagonals are those with two pairs of adjacent sides the same length - squares, rhombuses, and "kite" shapes.These are all special cases of "orthodiagonal" quadrilaterals. All orthodiagonal quadrilaterals will adhere to the rule that the sum of the squares of the lengths of two opposite (nonadjacent) sides will equal the sum of the squares of the lengths of the other two sides; for successive sides of lengths a, b, c, and d, we have:a2 + c2 = b2 + d2This formula will be true for all orthodiagonal quadrilaterals and any quadrilateral for which this is true will be orthodiagonal (i.e. the diagonals will be perpendicular).

They are 4 sided quadrilaterals such as a square, a rhombus and a kite.

A square, a rhombus and a kite are three examples of quadrilaterals that have perpendicular diagonals that intersect each other at right angles.

It makes sense because it is true. There are other quadrilaterals whose diagonals are perpendicular.