I'm going to go out on a limb and assume that
y2 8y c
actually means
y^2 + 8y + c
c = 16 makes a perfect square:
(y + 4)^2
= (y+4)*(y+4)
= y^2 + 8y + 16
81.
6.25
26
If the value applied in the radical is not a perfect square, it is irrational. 25; 400; and 625 are perfect squares and are rational when applied in a radical.
The radicand is the value under the radical symbol.
What value, in place of the question mark, makes the polynomial below a perfect square trinomial?x2 + 12x+ ?
81.
64
The answer will depend on what c is!If the trinomial is ax^2 + bx + c then the required value of c is (b^2)/(4a)
-12
144
(b/2)^2= 64
48
There are infinitely many possible answers: c = ±4x + 33
x2 + 22x + 121 to get this divide 22 by 2... then square the answer you get from that 22/2 = 11 112 = 121
-26
6.25