325 square inches
Area of a rectangle = length X height = 3*13 = 39 square feet.
if a rectangle has width of 5 and diagonal with lenght of 13, what is the area of the rectangle? Use Pythagoras' theorem to find the length of the rectangle which will be 12 5*12 = 60 square units
9 x 13 = 117 square inches
Area = Length * Width = 13 ft * 6 ft = 13*6 sq ft = 78 sq ft
If the area is 117 square meters and the width is 9 meters we can find the length by dividing: 117 / 9 = 13 The length is 13 meters
A rectangle has deminsions of 13 cm long and 78 cm wide.What is the area of the rectangle? A rectangle has deminsions of 13 cm long and 78 cm wide.What is the area of the rectangle?
add 21 and 13 and double the answer!
To get the area of a rectangle, you multiply length x width.
Perimeter = 2*(L + W) = 2*(8 + 5) = 2*13 = 26 km Area = L * W = 8 * 5 = 40 km2
Area of a rectangle = length X height = 3*13 = 39 square feet.
If the perimeter is 34 feet, and two of the sides are 4 ft. each (a total of 8 feet), then the other two sides are a total of 26 feet (34-8), or 13 feet each. So the rectangle is 13 feet long and 4 feet wide.
Any shape with such an area will do, for example: Draw a rectangle 1 cm wide and 47 cm long; Draw a rectangle 4.7 cm wide and 10 cm long; Draw an L shape with side lengths (going clockwise from the top) 1 cm, 19 cm, 13 cm, 2 cm, 14 cm, 21 cm.
156 feet is the area of a rectangle with a width of 12 feet and a height of 13 feet.
It is either 12 wide and 13 long or 13 wide and 12 long.
if a rectangle has width of 5 and diagonal with lenght of 13, what is the area of the rectangle? Use Pythagoras' theorem to find the length of the rectangle which will be 12 5*12 = 60 square units
The area of rectangle is : 78.0
Its area is 13 times 12 = 156 square inches.