Q: Why does 2 to the power of 0 equal 1?

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2 to the power 0 or 20 is equal to 1

Any number to the power of 0 equals 1.Therefore 2 to the power of 0 = 1

1. Anything to the power of 0 is equal to 1.

Yes, everything to the power of 0 equals 1.

0 to the power of 2 is 0, because to times 0 equals 0.

(2 - 1) * 0 = 0 Thus 2 - 1 = 0/0 = 0 and therefore 2 = 1

Yes. Any number to the 0 power is 1

This is equal to 1. On the Wikipedia page for imaginary numbers, they have a table, but here is a summary for in: n value of i^n -- ------ -4, 1 -3, i -2, -1 -1, -i 0, 1 1, i 2, -1 3, -i 4, 1 Notice there is a repeating pattern.

Both 30 and 20 are equal to 1. Any real number raised to the zero power is 1.

2 to the power of -2 is equal to 1/4.x to the power of -y is equal to 1/xy.

1 anything to the power of 0 is 1

Every digit in a binary number corresponds to power of two. So 0001 0101 is equal to 0*2^7 + 0*2^6 + 0*2^5 + 1*2^4 + 0*2^3 + 1*2^2 + 0*2^1 + 1*2^0, which equals 0+0+0+16+0+4+0+1, which equals 21.

Examples may give you an amazing idea of how to do it : 2 to the power of 0 is = 1 2 to the power of 1 is = 2 2 to the power of 2 is = 4 2 to the power of 3 is = 8 2 to the power of 4 is = 16 why is the answer like that ? well 2 to the power of something is the same as 2*?, for examples : 2 to the power of 4 is the same as : 2*2*2*2=16 2 to the power of 5 is the same as : 2*2*2*2*2=32 Do you understand now ? XD

The integers less than or equal to 2 are: {2, 1, 0, -1, -2, -3, ...}

2

Any number to the power of zero is 1, because if you raise x^0 by a power (in other words, if you multiply x^0 by x), you should get x^1, which is the same as x. and 1 times x is always equal to x, so x^0=1 1^0=1 2^0=1 7283423592348324236^0=1 x^0=1 You figure out what 40^0 is...

0 since anything to the power of 0 = 1

Any number to the power 0 is 1. Because 1 = x^n/x^n = x^(n-n) = x^0

In order to understand why everything to the zeroth power equal one, let's do some examples. 8^0 = 8^(1-1) = (8^1)(8^-1) = (8)(1/8) = 8/8 = 1 2^0 = 2^(2-2) = (2^2)(2^-2) = (4)(1/2^2) = (4)(1/4) = 4/4 = 1 (x + 1)^0 = (x + 1)^(1-1) = [(x + 1)^1][(x + 1)^-1] = (x+ 1)[1/(x + 1)] = (x + 1)/(x + 1) = 1

2^0=1 anything^0=1

No Actually... x^(-y) is equal to 1/x^y. 2^(-2) is equal to 1/2^2 which is equal to 1/4 or 0.25.

2 to the zero power = 1

0 (zero) because 1-1 = 0 and when u divide 0 by 2. it still equals 0

1

It is 1