Suppose x is an odd number, then x leaves a remainder when divided by 2. That is, x = 2m+1 (for some integer m).
Suppose y is an even number, then y is a multiple of 2 so suppose y = 2n (for some integer n).
Then x-y = 2m+1 - 2n = 2m-2n + 1 =2(m-n) + 1
Since m and n are integers, then m+n is an integer so that the sum gives 1 more than a multiple of 2. And that is what an odd number is!
7 is an odd number. If you subtract an odd number minus an even number, you will always get an odd number. There is no way to avoid this.
An odd number multiplied by another odd number will always equal an odd number. Therefore odd2 = odd x odd = odd number. eg 32 = 3 x 3 = 9. Take away 1 and you will have on even number.
Multiply two odd numbers Add an even and an odd Subtract an odd and an even
yes you can and get a positive # too.... unless the odd # is more than the even #
The negative number (-x) is first entered, then the rest. -x -(-y) When you subtract a negative, the minus and the negative cancel out, meaning you add.
7 is an odd number. If you subtract an odd number minus an even number, you will always get an odd number. There is no way to avoid this.
you will always have an odd number when you subtract an odd number from am even number
Odd. First subtract 1 less than your odd number, (which is obviously even) to get even - even, which is even. Then take off your spare 1 to finish up odd.
when an odd number is subtracted from an odd number the answer is an even number.
An odd number multiplied by another odd number will always equal an odd number. Therefore odd2 = odd x odd = odd number. eg 32 = 3 x 3 = 9. Take away 1 and you will have on even number.
The difference is an odd number.
No.
No
Multiply two odd numbers Add an even and an odd Subtract an odd and an even
yes you can and get a positive # too.... unless the odd # is more than the even #
Correct.
The negative number (-x) is first entered, then the rest. -x -(-y) When you subtract a negative, the minus and the negative cancel out, meaning you add.