80 is divisible by 2 because it's an even number; nevertheless, maybe it's because 2+2+2+2=8, or 2x4=8. So, it's divisible because 2x4=8, and 0 is 0. So 80 divided by 2 is 40. Plus it's math. :D
Any multiples of 80 are divisible by 80. Three examples: 80 / 80 = 1 : 160 / 80 = 2 : 800 / 80 = 10
No; it is divisible only by its factors (1, 2, 4, 5, 8, 10, 16, 20, 40, and 80).
The first number is 80
160 is divisible by all three numbers, 10, 2, and 5. 160 / 10 = 16 160 / 2 = 80 160 / 5 = 32
There are 80 such numbers.
Any multiples of 80 are divisible by 80. Three examples: 80 / 80 = 1 : 160 / 80 = 2 : 800 / 80 = 10
80 is divisible by 2,4,5,and 6
80 is not divisible by 234569 but is divisible by 10.
No; it is divisible only by its factors (1, 2, 4, 5, 8, 10, 16, 20, 40, and 80).
Factors of 80 = 1, 2, 4, 5, 8, 10, 16, 20, 40, 80.
No, 80 is composite. it is divisible by 1, 2, 4, 5, 8, 10, 20, 40, and 80
101
84
80 is divisible by 5 and 4 and is greater than 75
1, 2, 4, 5, 8, 10, 16, 20, 40, 80
1, 2, 4, 5, 8, 10, 16, 20, 40, 80
80 is an even number, thus it is divisible by 2; 80/2 = 40. 40 is also even, so it too is divisible by 2; 40/2 = 20. The same applies to 20; 20/2 = 10, and to 10; 10/2 = 5. Since both 2 and 5 are prime numbers, the prime factorization of 80 is 24 X 5.