Let's take a simple example to illustrate the concept.
A pitch is thrown by a pitcher. It starts at zero velocity (in his hand) and reaches a final velocity of 100 mph. Average velocity will be (100 + 0)/2 = 50 mph
Obviously the maximum velocity is 50 X 2 = 100 mph
However this is only true if the initial velocity (or the final velocity for a ball slowing down) is zero.
Because velocity is a measurement of change of speed rather than an average constant speed. To get the average speed (as you rightly said) - you divide the total distance travelled by the time taken. The average velocity is the change in speed over time (either an increase or decrease).
since kinetic energy is proportional to the square of velocity it is multiplied by 2 x 2 which is 4
average velocity is the displacement over time while instantaneous velocity refers to the velocity of an object at one point or at as pecific point of time. *displacement is the difference between the initial position and the final position of an object. (distance 2 - distance 1)
Use s=ut+0.5at^2 (^2 notation for squared)Or calculate the final velocity from the known variables (Initial Velocity, Acceleration and Time)v=u+at Where V = Final Velocity, u = Initial Velocity, a = Acceleration, t = TimeThen calculate displacement (s) using s=0.5(u+v)t
displacement = (final velocity square + initial velocity sq. )/ 2 * acceleration
The braking time is 2 - 1.5s = 0.5s. The final velocity, if the object comes to a stop, is 0m/s.
since kinetic energy is proportional to the square of velocity it is multiplied by 2 x 2 which is 4
Average speed = 1/2 (initial speed + final speed) Time = (distance)/(average speed)
To calculate the velocity of an object you can use the formula v=d/t. v=velocity, d=distance, and t=time. You can also calculate velocity using a=change in v/change in t, v(final)=v(initial)+at, v(average)=v(final)+v(initial)/2, or v(final)^2=v(initial)^2+2ad, or p=mv.
Change in Distace= Initial velocity multiplied by change in time plus half the accleration times change in time squared x=VoT+.5aT^2 Final velocity squared=Intial velocity squared plues two times accleration times change in distance Vf^2=Vo^2+2aX Final velocity= Initial velocity plus accleration times change in time Vf=Vo+aT
The area between the graph and the x-axis is the distance moved. If the velocity is constant the v vs t graph is a straight horizontal line. The shape of the area under the graph is a rectangle. For constant velocity, distance = V * time. Time is the x-axis and velocity is the y-axis. If the object is accelerating, the velocity is increasing at a constant rate. The graph is a line whose slope equals the acceleration. The shape of the graph is a triangle. The area under the graph is ½ * base * height. The base is time, and the height is the velocity. If the initial velocity is 0, the average velocity is final velocity ÷ 2. Distance = average velocity * time. Distance = (final velocity ÷ 2) * time, time is on the x-axis, and velocity is on the y-axis. (final velocity ÷ 2) * time = ½ time * final velocity ...½ base * height = ½ time * final velocity Area under graph = distance moved Most velocity graphs are horizontal lines or sloping lines.
There are 3 formula 1. Final velocity = starting velocity + (acceleration)(time) 2. Final velocity^2 = starting velocity^2 + 2(acceleration)(distance) 3. Distance = (starting velocity)(time) + 1/2(acceleration)(time^2) Use whichever you can use.
Kinematics. Final velocity squared = initial velocity squared + 2(gravitational acceleration)(displacement)
i think it's 2
the final velocity assuming that the mass is falling and that air resistance can be ignored but it is acceleration not mass that is important (can be gravity) final velocity is = ( (starting velocity)2 x 2 x acceleration x height )0.5
It is calculated as 1/2 mass multiplied by velocity squared
There are two methods, it depends on what variables you have: 1. Subtract the initial velocity from the final velocity and divide that whole term by the time (Vf- Vi)/t = a 2. Square both the initial velocity and the final velocity and subtract the squared inital velocity from the squared final velocity and that answer by two times the distance (Vf^2 - Vi^2)/2d = a
average velocity is the displacement over time while instantaneous velocity refers to the velocity of an object at one point or at as pecific point of time. *displacement is the difference between the initial position and the final position of an object. (distance 2 - distance 1)