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Why is the sum of consecutive odd integers always a multiple of 4?
Wiki User
∙ 13y ago
It is quite easy to prove this using algebra.
Suppose x is the smaller of the two odd integer. The fact that x is odd means that it is of the form 2m + 1 where m is an integer.
[m integer => 2m is an even integer => 2m + 1 is odd]
The next odd integer will be x + 2, which is (2m + 1) + 2 = 2m + 3
The sum of these two consecutive odd integers is, therefore,
2m + 1 + 2m + 3 = 4m + 4 = 4(m + 1)
Since m is an integer, m+1 is an integer and so 4(m + 1) represents a factorisation of the answer which implies that 4 is a factor of the sum. In other words, the sum is a multiple of 4.
Wiki User
∙ 13y ago
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What are two consecutive integers for 52?
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Why can you not find 2 consecutive odd numbers that have a sum of 29?
29 cannot be the sum of two odd integers. The sum of two odd integers is always an even integer.
The sum of two consecutive odd integers?
Are not all integers spaced out to be odd then even then odd then even etc (eg 1,2,3,4,5,6,7,8,9,10, etc) and therefore there is no such thing as two consecutive odd integers.
What is the sum of 3 consecutive odd integers that is at least 162 the minimum sum?
3 odd integers must total an odd number. 3 consecutive odd integers must total a multiple of 3. The lowest number greater than 162 which satisfies these requirements is 165, ie 53 + 55 + 57
What are the two consecutive integers with a sum of 58?
There are no two consecutive integers that sum to 58. With two consecutive integers, one is even, the other is odd. The sum of an even number and an odd number is odd. 58 is even so cannot be the sum of two consecutive integers.
