Because the derivative of e^x is e^x (the original function back again). This is the only function that has this behavior.
Derivative of sin x = cos x, so chain rule to derive 8x = 8 , answer is 8cos8x
I'm assuming your question reads "What is the derivative of 3cos(x2)?" You must use the Chain Rule. The derivative of cos(x2) equals -sin(x2) times the derivative of the inside (x2), which is 2x. So... d/dx[3cos(x2)] = -6xsin(x2)
f'(x)= 0x^-1=0anything multiplied by zero equals zero
Calculate the derivative of the function.Use the derivative to calculate the slope at the specified point.Calculate the y-coordinate for the point.Use the formula for a line that has a specified slope and passes through a specified point.
When you solve for the 2nd derivative, you are determining whether the function is concave up/down. If you calculated that the 2nd derivative is negative, the function is concave down, which means you have a relative/absolute maximum, given that the 1st derivative equals 0. To understand why this is, think about the definition of the 2nd derivative. It is a measure of the rate of change of the gradient. At a maximum, the gradient starts positive, becomes 0 at the maximum itself and then becomes negative, so it is decreasing. If the gradient is going down, then its rate of change, the 2nd derivative, must be negative.
Yes, the derivative of xi with respect to x equals i. Is that what you were trying to ask?
The derivative of 10x is 10. This is irrespective of the value of x.
x = 10x, so derivative = 10
No. It's physics.
The derivative of cos(x) equals -sin(x); therefore, the anti-derivative of -sin(x) equals cos(x).
Find the derivative of Y and then divide that by the derivative of A
The "double prime", or second derivative of y = 5x, equals zero. The first derivative is 5, a constant. Since the derivative of any constant is zero, the derivative of 5 is zero.
- the derivative with respect to x is 40y - The derivative with respect to Y is 40xSo, since both x and y equal 2, both derivatives yield 40*2 = 80
Following the correct order of operations: derivative of x^2 + 6/2 = derivative of x^2 +3, which equals 2x
(xlnx)' = lnx + 1
This is not Calculus. 6 + (2*4 = 8) = 14.
you have to first find the derivative of the original function. You then make the derivative equal to zero and solve for x.