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Prime factorization is the finding which Prime number multiply to get to make the original number.

44: 1, 2, 4, 11, 22, 44

Prime Factors: 2, 11

Prime Factorization: 2 x 2 x 11

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Q: Write 44 of a product of prime factors?

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It is: 2*2*11 = 44

It is: 2*2*11 = 44

44 = 2 x 2 x 11

2x2x11

As a product of its prime factors: 2*2*11 = 44

It is: 2*2*11 = 44

44 is equal to 11 x 2 x 2. The product of any set of prime factors of a number is equal to the number itself.

As a product of its prime factors: 2*2*11 = 44

44 = 2 x 2 x 11

The prime factors of 44 are: 2, 11

Prime Factors of 44 = 2, 2, 11

2 x 2 x 11

To find the hcf of three numbers you first need to write them as the product of their prime factors: 11 = 11 88 = 2x2x2x11 44 = 2x2x11 The next step is to identify any common prime factors. In this case, all three numbers have a prime factor of 11. Therefore the hcf of 11, 88 and 44 is 11.

The Prime Factors of 44 are 2, 11

1,2,4,11,22,44 2 and 11 are prime.

The prime factors of 44 are: 2 and 11

2 x 2 x 11

The factors of 44 are: 1 2 4 11 22 44The prime factors are: 2 11

The prime numbers (factors) of 44 are: 2 and 11

2 and 11 are prime and factors of 44.

44 22,2 11,2,2

44 = 2 * 2 * 11

Every counting number(except 1) can be expressed as product of prime numbers. So 44 can be expressed as product of prime numbers: 44 = 2x2x11 = 22x11.

The factors of 44 are: 1 2 4 11 22 44. The prime factors are: 2 x 2 x 11

It is: 2*2*11 = 44

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