int n, N;
N = some even number
for (n=2; n<=N; n+=2) printf ("%d\n", n);
printf ("%d", 51*350);
Reference:http:cprogramming-bd.com/c_page2.aspx# strange number
find even number in array
In visual basic: Module Module1 Sub Main() Dim Inst As Integer For Inst = 0 To 100 Step 2 Console.WriteLine(Inst) Next End Sub End Module
AnswerIf A=10, B=2... Then the algoritm is :-STEP1 : START.STEP2 : A=10.STEP3 : B=02.STEP4 : C=A-B.STEP5 : PRINT C.STEP6 : STOP.AnswerYou cannot print every even number in descending order, because there is no greatest even number. Or you want something like this: infinityinfinity-2infinity-4Answerstep 1: start step 2: Input Nstep 3: If N
CLS PRINT "PROGRAM: Print squares of all even numbers from 1 to 20" PRINT PRINT "number", "squared" PRINT FOR number% = 1 TO 20 IF number% MOD 2 = 0 THEN PRINT number%, number% * number% END IF NEXT END
You can use int i; for (i = 10; i <= 50; i += 2) {//print i} as a program to print even numbers between 10 and 50.
Reference:http:cprogramming-bd.com/c_page2.aspx# strange number
Start print "the sum of all even numbers is infinite" end
find even number in array
for (int i = 2; i < 10; i ++) printf("%d\n", i); You did say even and odd numbers between 1 and 10. That's allnumbers between 1 and 10.
Code Below: <?php $j = 100; // Set limit upper limit echo "Even Numbers are: <br/>"; for($i=1;$i<=$j;$i++) { if($i%2) { continue; } else { echo $i."<br/>"; } } ?>
printf ("100+...+200=%d\n", ((100+200)/2)*(202-100)/2);
# include<stdio.h> void main() { int i = 1; while(i<11) { if(i%2==1) { printf("\n%d",i); } i++; } }
#include(stdio.h) int main ()
In BASIC: 10 INPUT X: IF X = 999 THEN STOP ELSE PRINT X; 20 IF X/2 = INT(X/2) THEN PRINT "EVEN" ELSE PRINT "ODD" 30 GOTO 10
In visual basic: Module Module1 Sub Main() Dim Inst As Integer For Inst = 0 To 100 Step 2 Console.WriteLine(Inst) Next End Sub End Module
5 CLS 10 REM PROGRAM TO ADD FIRST 7 EVEN NUMBERS 20 EV = 2 30 SUM = 0 35 PRINT "NUMBERS="; 40 FOR I = 1 TO 7 50 SUM = SUM + EV 55 PRINT EV; 60 EV = EV + 2 70 NEXT I 95 PRINT 80 PRINT "SUM="; SUM 90 END http://arnavguddu.6te.net/