How do you write a program to find whether a number is a perfect square in java?

Answer 1

Example:

int x, y;

x = 5;

y = x * x; // square of x

System.out.println("The square of " + x + " = " + y);

Put all this in your main() method. Most Java IDEs will generate the main() method automatically.

Answer 2

OK, so here it is:

import java.lang.Math;

import java.util.Scanner;

public class Square

{

public static void main(String[] args)

{

Scanner input = new Scanner(System.in);

System.out.println("Please enter a number to be processed:");

double num = input.nextInt();

if((Math.sqrt(num) * 10) % 10 == 0.0)

{

System.out.println("Is a square!");

}

else

{

System.out.println("Is not a square.");

}

}

}

Answer 3

:/ Just square root the number with a calculator. If it isn't "just" a number, then its not a perfect square.