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Q: Write a program to multiply 33 matrix.?

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33/100 is the same as .33 You can do this directly saying the decimal as 33 hundreds. Alternatively, write 0.33 as 0.33/1 and multiply numerator and denominator by 100. This yields 33/100.

You can write 33 as "thirty three."

Fix 33 table changes : macierz1[][],macierz2[][],... and its size (write size to brackets) Fix a matrix to result : wynik[][], and int i,j. for(i=0;i<size_of_your_matrix;i++) for (i=0;i<size_of_your_matrix;i++) wynik[i][j]=macierz1[i][j]+...+macierz33[i][j]; Or instead of 33 changes: macierz[33][size][size] for(k=0;k<33;k++) for(i=0;i<size_of_your_matrix;i++) for (i=0;i<size_of_your_matrix;i++) wynik[i][j]=wynik[k][i][j]+macierz[k][i][j]; (dont forget about initializing wynik as 0 in 2nd case)

1 x 33, 3 x 11

Simply multiply 33 by any number, and you will have your answers.

33 x 33 = 1,089

.33

33/100

33 = thirty-three.

0.33

1/2 = 50% 1/4 = 25% divide the top number by the bottom number and multiply by 100. 3/4 = .75 multiply by 100 = 75% 33/34 = .970 multiply by 100 = 97%

int main() { int a[3][3] = {{1,2,3},{4,-5,6},{7,8,9}}; int smallest = INT_MAX; for (size_t row=0; row<3; ++row) { for (size_t col=0; col<3; ++col) { if (a[row][col]<smallest) smallest = a[row][col]; } } assert (smallest==-5); }

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