0
x2+12x+36=0 2x+12x+36=0 14x+36=0 14x=-36 x=-36/14 x=-2 4/7
Wiki User
∙ 14y ago
Add your answer:
Earn +20 pts
What is x squared plus 12x plus 36 equals?
x2 + 12x + 36 = 0(x + 6) (x + 6) = 0x+ 6=0 ;x + 6 = 0x = -6 ; x = -6
Factor the following polynomial x2 plus 12x plus 32?
x2 + 12x + 32 = (x + 8)(x + 4)
What is the factorization of the polynomial x2 plus 12x plus 20?
x + 12x + 20 = (x + 10)(x + 2)
What number must you add to complete the square x2 plus 12x equals 16?
Add? I will show you the process. X^2 + 12X = 16 halve the linear term (12), square it and ADD it to both sides X^2 + 12X + 36 = 16 + 36 factor the right side; gather terms right (X + 6)^2 = 52 (X + 6)^2 - 52 = 0 (-6,-52) vertex of function As you see 36 was added to both sides
Factor x2 plus 13x plus 36 completely?
x2 + 13x + 36 = (x + 9)(x + 4)
X2 - 12x plus 36?
x2-12x+36 = (x-6)2
X2-12x plus 36 equals 11?
x=5/2*sqr(3)
How can you rewrite equation x squared plus 12x plus 5 equals 3?
x2+12x+5 = 3 x2+12x+5-3 = 0 x2+12x+2 = 0
What is x squared plus 12x plus 36 equals?
x2 + 12x + 36 = 0(x + 6) (x + 6) = 0x+ 6=0 ;x + 6 = 0x = -6 ; x = -6
X2 plus 12x-6 equals 0?
If you're looking to solve for x, you can do so as follows: x2 + 12x - 6 = 0 x2 + 12x + 36 = 42 (x + 6)2 = 42 x + 6 = ± √42 x = -6 ± √42
Factor X2-12x plus 36 equals 0?
=>2x - 12x + 36 = 0 =>10x = 36=>x = 3.6Another contributor's answer:This is a quadratic equation question:x2-12x+36 = 0When factorised:(x-6)(x-6) = 0
X2 - 12x 36?
x2 - 12x + 36 = (x - 6)2
What is the square of x2 plus 12x plus 20 equals 0?
168
X2 plus 12x-64 equals 0?
x2 + 12x - 64 = 0 ∴ (x + 16)(x - 4) = 0 ∴ x ∈ {4, -16}
What is the constant term in X2 plus 12x minus 13 equals 0?
It is -13.
What is the factorization of the trinomial -x2 plus 12x plus 28?
x2+12x+28Improved Answer:--x2+12x+28 = (-x+14)(x+2) when factored
What is the perimeter of the curve x2 plus y2-12x-8y-43 equals 0?
Let's first reformat it: x2 + y2 - 12x - 8y - 43 = 0 x2 - 12x + 36 + y2 - 8y + 16 = 43 + 36 + 16 (x - 6)2 + (y - 4)2 = 95 So this equation defines a circle, with a center point at (6, 4) and a perimeter (i.e. circumference) of √95.
