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x^3y = 2, y = 4
Substitute 4 for y:
(x^3)(4) = 2
x^3 = 8
x = 2
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Factor the trinomial x2 - 2x - 8 Write each factor as a polynomial in descending order?
x**2-2x-8 Multiply first 2 terms: 1*-8=-8 Find factors that add up to second term: -2, 4 --> -2+4 = 2 -4,-2 --> -4+2 = -2 Rewrite: x**2+2x-4x-8 Factor sets of terms x**2+2x=x(x+2) -4x-8=-4(x+2) x**2+2x-4x-8 = x(x+2)-4(x+2) Factor x(x+2)-4(x+2) = (x+2)(x-4)
X-2 times x plus 4 divided by x squared - 4?
x-2(x)+4/x^2 -4=x-2x+4/x^2 -4=-x-4+4/x^2
How do you find the cube root of -8?
Don't know how you find it but I guess the answer is -2. -2 x -2 =4 4 X -2 = -8
How do you factor x squared plus x minus one half?
(x^2+x-1/2)= x(x+1)-1/2 [x + (1 - square root of 3)/2][x + (1 + square root of 3)/2] = 0 Check it: x^2 + x/2 + (square root of 3)x)/2 + x/2 + 1/4 + (square root of 3)/4 - (square root of 3)x/2 - (square root of 3)/4 - 3/4 = 0 x^2 + x/2 + x/2 + [(square root of 3)x]/2 - [(square root of 3)x]/2 + (square root of 3)/4 - (square root of 3)/4 + 1/4 - 3/4 = 0 x^2 + x - 2/4 = 0 x^2 + x - 1/2 = 0 How to find this roots: Using the completing the square method: x^2 + x - 1/2 = 0 x^2 + x = 1/2 x^2 + x + 1/4 = 1/2 + 1/4 (x + 1/2)^2 = 3/4 x + 1/2 = (plus & minus)(square root of 3/4) x = -1/2 + (square root of 3)/2 x = - 1/2 - (square root of 3)/2
If y equals 4 when x equals 2 find y when x equals 16?
y=4 and x=2. find y when x=16.this is a simple ratio problem that becomes 4/2=y/16simplifying the equation in terms of "y", becomes y= 16 x (4 / 2)thus, y = 32as a quick check, realizing that y is twice as big as x or y=2x, also becomes y=32
How do you factor by grouping x3y 2x2y xy3?
xy(x^2 + 2x + y^2)
What is 4xy plus x3y plus yx2 plus yx plus 3yx simplified?
4xy + x3y + yx2 + yx + 3yx = x3y + x2y + 8xy = (xy)(x2y + x + 8)
How can you use 2 X 10 to find 4 X 10?
Just double the 2 X 10 to find 4 X 10.
How do you find zeros on each function?
Set the equation equal to zero. For example, take the function F(x) = x^2 - 4 Find the zeroes by x^2 - 4 = 0 x^2 = 4 sqrt(x^2) = sqrt(4) x = +/- 2
How do you find zeros of a function in intercept form?
if you want to find the zero/null /x-intercept of any given function you have to find the x that makes it zero. therefore if f(x) = 2x +4 you have to put f(x) = 0 0 = 2x +4 2x = -4 x=-2 if you subsitute -2 for x you will find that the function f(x) will equal zero f(x)= 2 * (-2) +4 f(x) = -4 +4 f(x) = 0 if you have more complex functions like squared your approach will look something like this say g(x) is a function of x² g(x)=(x-2)² +4 set g(x)= 0 0= (x-2)² -4 4= (x-2) ² + or - radical (4) = x -2 2 + radical (4) = x or 2 -radical (4) = x x=4 or x = 0 remember radicals always have two solutions
Write three ways to find 3 x 2 x 4?
3 x 2 x 4 = 24 (3 x 2) x 4 = 6 x 4 = 24 3 x (2 x 4) = 3 x 8 = 24 2 x (3 x 4) = 2 x 12 = 24
What is the answer of 2 plus 2 equals x please find x?
4
How do you find the prime factorization of 4?
Divide it by 2. 2 x 2 = 4
How could you find the LCM of 4 and 50?
2 x 2 = 4 2 x 5 x 5 = 50 2 x 2 x 5 x 5 = 100, the LCM
Find three different ways to show factorizations strings of factors of the number 16?
2 x 2 x 2 x 2 2 x 8 4 x 4
Find the indicated product of FOIL (x-2)(x plus 2) last?
X^2-4
How do you find the solution of 2x equals 4?
Divide both sides by two. x = 2 2x=4 2x/2=4/2 2x/2=1x=x 4/2=2 x=2
