it equals x1 it equals x1
Your answer will depend on the parameters of the instructions. If you're looking for the first derivative, simply use the product rule by changing the denominator to a negative exponent and bringing it up (take the negative square root of the quantity x-2 to the top). Then, follow the rules of calculus and algebra. Wow, that's a mess. Let's see... you get "the quantity x cubed plus 6x squared plus 3x plus 1 times the quantity -1(x-2) raised to the negative second plus the quantity x-2 raised to the negative first times the quantity 3x squared plus 12x plus 3." This is because of the Product Rule. Simplifying (by factoring out (x-2) raised to the negative second and combining like terms) gives us "(x-2) raised to the negative second times the quantity 2x cubed minus 24x minus 7." This can also be written as "2x cubed minus 24x minus 7 all over the quantity x-2 squared." f'(x)= 2x^3-24x-7 (x-2)^2
2 9 1 plus 1 is 2.
X2 + 3X - 18 Ask yourself, what two factors of - 18 add to 3? (X + 6)(X - 3) -----------------
This is a quadratic equation, and so you it falls under the rule: ax squared + bx + c. This means you need to times the 2x squared by 5, which is 10. Then you need to find the factors of ten, i.e. 2 and 5, 10 and 1. You need to find the pair of factors that add to make 7x, which would be 2 and 5. you then need to put these into the equation - it would become 2x squared + 2x (as one equation) and 5x + 5 would be another equation. we can see that 2x squared and 2x have 2x in common, and so the answer for that would be 2x (x + 1). the second equation would be 5 (x + 1). the two equations have x + 1 in common, and that would make up the first set of brackets. you then add the rest (2x +5) and your answer would be (x+1) (2x+5). FOIL is a different method used for 'easier' equations - less complicated. :)
Your equation is not clear I can understand it in two ways (x2-16)/x-4+x2=16 x=-4.59486 x=-0.793499 x=4.38835 or x2-(16/x)-4+x2=16 x=3.50466 x=-0.864641 x=-2.64002
By factoring I get x-3 divided by x+3
no
One.
15 over 16
4
Find the square root of one side squared plus the second side squared.
17.
A squared plus B squared equals C squared, where C is the hypotenuse of a right triangle and A and B are the other two sides is true and is one way of expressing the Pythagorean Theorem.
Two over eight plus four over eight plus one over eight equals seven over eight
Two is a prime factor of that equation.
X= plus or minus 1
Two equations: a linear one in y and a quadratic in x.