x(9+x)
Let the number be x and if 9+2x = 15 then x equals 3
9 x 9 x 9 x 9 x 9, or 9^5, is equal to 59049.
2(x + 9) = 2x + 18
The distributive property is: a ( b + c) = ab + ac so you need a sum. Remember that 44 is 40 + 4, that is your sum. so... 9 x 44 = 9 (40 + 4) = (9 x 40) + (9 x 4)
(4 x 9) + (5 x 9) = (9 x 9)c= 81
x times the sum of x and 9 x times (x times 9) x(9x) 9 times x[squared] 9x[squared]
5(x^2 + y)
5 (9+x) Where x is the "a number"
Let the number be x and if 9+2x = 15 then x equals 3
x + 9 = n
9 x 9 x 9 x 9 x 9, or 9^5, is equal to 59049.
2(x + 9) = 2x + 18
The distributive property is: a ( b + c) = ab + ac so you need a sum. Remember that 44 is 40 + 4, that is your sum. so... 9 x 44 = 9 (40 + 4) = (9 x 40) + (9 x 4)
It is: x(x+11) or x^2 +11x
(2 x 9) + (3 x 9) = 5 x 9 = 45
(4 x 9) + (5 x 9) = (9 x 9)c= 81
0 x 9=0 1 x 9=9 2 x 9=18 3 x 9=27 4 x 9=36 5 x 9=45 6 x 9=54 7 x 9=63 8 x 9=72 9 x 9=81 10 x 9=90 The trick is in the answer to every sum the ten gets bigger and the unit gets smaller. e.g: 8 x 9=72 9 x 9=81