Firstly, the probability when tossing a coin and getting a head or tail is 1/2, then rolling a die, there are 6 sides so the chance of rolling any number is 1/6, there are 2 chances of rolling greater than 4 ie 5 and 6, so the probability of rolling a 5 or 6 in 1/3, as these are independent events you multiply the probability getting a heads of tails, (1/2) by the probability of rolling a five or six, (1/3) which gives you 1/6 or 0.1666 recurring.
It is 0.375
The probability of tossing an odd number (assumed on a die) is 3 in 6 or 1 in 2. The probability of tossing a tail (assumed on a coin) is 1 in 2. Since these are unrelated events, and the question said "and", simply multiply the probabilities to get 1 in 4.
The probability of eventually throwing a prime number is 1. On a single throw, of a fair die, the probability is 1/2.
-3/12
The probability is 1. (aka 100% aka 6/6)
3/8. And the coin tossing is totally irrelevant.
3/16
It is 0.375
First probability of getting 2 is one in six: 1/6probability of getting no greater than 4 is two chances in six (must be a 5 or 6): 2/6=1/3so probability = 1/6*1/3= 1/18.
The probability of tossing an odd number (assumed on a die) is 3 in 6 or 1 in 2. The probability of tossing a tail (assumed on a coin) is 1 in 2. Since these are unrelated events, and the question said "and", simply multiply the probabilities to get 1 in 4.
the probability is 4 out of 6
1/2, 0.5, 50%, or half a chance.
1/2 * 1/2 = 1/4 1/2= probability of landing an even number 1/2 = probability of landing a heads
The probability of eventually throwing a prime number is 1. On a single throw, of a fair die, the probability is 1/2.
The probability of tossing a 1 or 2 on a six sided die is 2 in 6, or 1 in 3.
There are 36 possibilities when rolling two six sided die. 15 of them result in a prime number (2,3,5,7,11) So the probability is 15 in 36 or a 5 in 12 chance.
there are three distinct outcomes1,3or5. But there is no probability which will come.