Of course. You have a choice of several different lovely arrangements:
18 Chairs into equal rows - 6 x 3 2 x 9 18 x 1
The number of rows and the number of chars in that row give you the factor pairs of 18. If you list the number of rows when the 18 chairs can be arranged in rows with an equal number in each row, then this list is the factors of 18. 18 chairs can only be arranged in: 1 row of 18 chairs (1 × 18 = 18) 2 rows of 9 chairs (2 × 9 = 18) 3 rows of 6 chairs (3 × 6 = 18) 6 rows of 3 chairs (6 × 3 = 18) 9 rows of 2 chairs (9 × 2 = 18) 18 rows of 1 chair (18 × 1 = 18) The factors of 18 are thus: 1, 2, 3, 6, 9, 18.
Think of the chairs as arrays. The dimensions of the arrays give you the factors of 18.
It's a concrete way to visualize an abstract concept. If you can arrange the chairs (or blocks or stones or any other items) in even rows, those dimensions are factors. You will find you will be able to arrange them in 2 rows of 9 and 3 rows of 6. You will not be able to arrange them in rows of 4 or 5 without having some left over. The factors of 18 are 1, 2, 3, 6, 9 and 18.
63
18
No.
18 Chairs into equal rows - 6 x 3 2 x 9 18 x 1
The number of rows and the number of chars in that row give you the factor pairs of 18. If you list the number of rows when the 18 chairs can be arranged in rows with an equal number in each row, then this list is the factors of 18. 18 chairs can only be arranged in: 1 row of 18 chairs (1 × 18 = 18) 2 rows of 9 chairs (2 × 9 = 18) 3 rows of 6 chairs (3 × 6 = 18) 6 rows of 3 chairs (6 × 3 = 18) 9 rows of 2 chairs (9 × 2 = 18) 18 rows of 1 chair (18 × 1 = 18) The factors of 18 are thus: 1, 2, 3, 6, 9, 18.
1 row of 180 - 2 rows of 90 - 3 rows of 60 - 4 rows of 45 - 5 rows of 36 - 6 rows of 30 - 9 rows of 20 - 10 rows of 18 - 12 rows of 15 - 15 rows of 12 - 18 rows of 10 - 20 rows of 9 - 30 rows of 6 - 36 rows of 5 - 45 rows of 4 - 60 rows of 3 - 90 rows of 2 - 180 rows of 1 - total of 18 ways within the limits of the question
Idk but i think you put them in 5 rows of 6 cause 6 times 5 = 30
Yes, with 9 chairs in each row.
Think of the chairs as arrays. The dimensions of the arrays give you the factors of 18.
It's a concrete way to visualize an abstract concept. If you can arrange the chairs (or blocks or stones or any other items) in even rows, those dimensions are factors. You will find you will be able to arrange them in 2 rows of 9 and 3 rows of 6. You will not be able to arrange them in rows of 4 or 5 without having some left over. The factors of 18 are 1, 2, 3, 6, 9 and 18.
one row of 18 chairs two rows of 9 chairs three rows of 6 chairs
No because you can't put into even rows
2 rows of 18 squares3 rows of 12 squares4 rows of 9 squares6 rows of 6 squares9 rows of 4 squares12 rows of 3 squares18 rows of 2 squares36 rows of 1 squareI would not count "1 row of 36 squares", because you only have a single row that cannot equal another row (there is only one rowafter all). If this is for homework, I would state your reasoning for excluding (or including) that set. Count all the options up, and you have 8 different ways you can arrange the rows with the exclusion.