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Q: What are the four two digit multiples of 3?

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There are 30 two-digit multiples of 3 plus 18 two-digit multiples of 5 minus 6 two-digit multiples of both. Answer: 42

60 numbers

30, 60 and 90.

There are none.

45 multiples of 2 plus 30 multiples of 3 minus 15 multiples of 6 equals 60 numbers

100, 110 and 120 are 3 digit multiplies of 10.

The prime factors of 81 are 3, 3, 3, and 3 - so the only two-digit factor is 27, which is 3 x 3 x 3.

6134

You put the four digit number at the top of the three digit number and you do the same thing as you would do with a two digit number with a 3 digit number.

Multiples of 30 from 120 to 990

lcm(2, 3, 5) = 30 → 2 digit common multiples are 30, 60, 90.

There are 49 3-digit numbers - from 108 to 990 inclusive.

99

50 of them.

They are: one, two, three, four!

All integers have an infinite amount of multiples.

The first four multiples of 3 are 3, 6, 9, and 12 . The first four multiples of 6 are 6, 12, 18, and 24 .

Not necessarily. Consider 444. The digits are not different. The first and second digits are not multiples of 3 The first digit is not greater than the second digit. In spite of all that, 444 is a 3-digit number

Any multiple of four must be even; any number ending in three is odd. Look at the multiples of four from 1 to 9. They are in the order : 4,8,12,16,20,24,28,32,36. Now, any number when multiplied by 4, will have the one's digit as the one's digit of the above multiples In the above multiples, no multiple has 3 as the one's digit, i.e., no multiple ends in three. Take an example. 15x4 will have 0 in the one's digit because 5x4 = 20 and has 0 in the one's place.

-3

There are 450 such numbers.

Multiple of both 2 and 3 <=> multiple of 6 So require 2 digit multiples of 6. 2*6 = 12 and 16*6=96 So the answer is 16-2+1 = 15

12, 24, 36, 48, 60, 72, 84, and 96 are.

12, 24, 36, 48, 60, 72, 84, 96

The answer is 4. You get the answer by trying the example of the largest two digit number, 99. 99 x 99 = 9801. This has four digits, so you can't get more digits than this by multiplying two two digit numbers. * * * * * True, but you CAN have fewer: 10*10 = 100, which is only three digits! 1490 of the 8100 2 digit x 2 digit multiples have products of 3 digits, the rest have 4 digit products.